What amount of heat absorbs 50 g of steel (ce = 0.115 cal / g. ° C) that
does its temperature vary by 25 ° C?
Answer:
143.75cal
Explanation:
Given parameters:
Mass of steel = 50g
Specific heat capacity of the steel = 0.115cal/g°C
Temperature = 25°C
Unknown:
Amount of heat = ?
Solution:
The amount of heat to cause this temperature change is dependent on mass and specific heat capacity of the substance.
Amount of heat = m C (ΔT)
m is the mass
c is the specific heat capacity
ΔT is the temperature change
Now insert the parameters and solve;
Amount of heat = 50 x 0.115 x 25
Amount of heat = 143.75cal
Answer:
This is the exact answer. Please give brainliest. The answer is 132.13952.
Explanation:
Answer:
Barium and sulpher are the elements that forms barium sulphide .
And its molecular fomula is BaS.
Explanation:
Answer:12.5
Explanation: Divide 50$ by the 4 hours and you will get 12.5 which is $12.50.
Answer:
1.54 liters.
Explanation:
If the liters increases by .27 for every 100ºC, then just multiply .27 by 2.
You'd then get 1.54, which is your answer.
Hope this helps!
