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vazorg [7]
3 years ago
11

A ferry approaches shore moving north waith a speed of 6.1 m/s relative to the dock. A person on the feery walks from one side o

f the ferry to the other moving east with a speed of 1.0 m/s relative to the feery
Physics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

6.18 m/s

Explanation:

Given that a ferry approaches shore, moving north with a speed of 6.1 m/s relative to the dock. A person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.0 m/s relative to the ferry Part. What is the speed of the person relative to the dock?

The speed of the person can be calculated by using pythagorean theorem.

Let the speed of the person = S

S^2 = 6.1^2 + 1^2

S^2 = 38.21

S = sqrt ( 38.21)

S = 6.18 m/s

Therefore, the speed of the person relative to the dock is 6.18 m/s

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A horizontal platform in the shape of a circular disk rotates on a frictionless bearing about a vertical axle through the center
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Answer:

10.93 rad/s

Explanation:

If we treat the student as a point mass, her moment of inertia at the rim is

I_r = mr^2 = 67.8*3.7^2 = 928.182 kgm^2

So the system moment of inertia when she's at the rim is:

I_1 = I_d + I_r = 274 + 928.182 = 1202.182 kgm^2

Similarly, we can calculate the system moment of inertia when she's at 0.456 m from the center

I_2 = I_d + 67.8*0.456^2 = 274 + 14.1 = 288.1 kgm^2

We can apply the law of angular momentum conservation to calculate the post angular speed when she's 0.456m from the center:

I_1\omega_1 = I_2\omega_2

\omega_2 = \omega_1\frac{I_1}{I_2} = 2.62*\frac{1202.182}{288.1} = 10.93 rad/s

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3 years ago
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The free body diagram represents Silly Sally hanging from a trapeze bar. Sally weighs 660 Newtons. What is the force in each of
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