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gizmo_the_mogwai [7]
2 years ago
12

7. How many milligrams are equal to 0.0268 pounds? (1 oz = 28.34 g, 16oz = 1lb)

Chemistry
1 answer:
Sphinxa [80]2 years ago
6 0

Answer: 12156.275515999867

12156 simplified repeated decimal.

Explanation:

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Write the Iconic Bond to Metals
Nutka1998 [239]

<u>Answer:</u> The ionic compound formed is magnesium chloride having formula MgCl_2

<u>Explanation:</u>

Ionic compound is defined as the compound which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Magnesium is the 12th element of the periodic table having electronic configuration of 1s^22s^22p^63s^2

This element will loose 2 electrons to form Mg^{2+} ion

Chlorine is the 17th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^5

This element will gain 1 electron to form Cl^{-} ion

So, for every 1 atom of magnesium, 2 atoms of chlorine are required. Thus, the chemical formula becomes MgCl_2

Hence, the ionic compound formed is magnesium chloride having formula MgCl_2

6 0
2 years ago
SO2________________.
Mashcka [7]

Answer:

a. Dipole-dipole bonding

Explanation:

SO2 has dipole-dipole bonding. This is because of the difference in the electronegativities  of Sulphur and oxygen. Moreover, the lone pair of electrons on S gives it bent shape with a net dipole  unlike CO2 which has a linear shape.( This why CO2 does not have any dipole moment).

So, the correct answer is a.

6 0
3 years ago
An oxide ion, O2–, has:
sergij07 [2.7K]

Answer:

the answer A- 8 protons and 10 electrons

6 0
2 years ago
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kap26 [50]
B. Holocaust
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3 0
3 years ago
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Calculate the eccentricity of an ellipse. The distance between the foci is 5.2 and the length of the major axis is 20.6.Round of
Dominik [7]

Answer:

The eccentricity of the ellipse is 0.252.

Explanation:

The eccentricity of an ellipse (c), dimensionless, can be determined by means of the following expression:

e = \frac{\bar c}{\bar a} (1)

Where:

\bar c - Distance between the foci, dimensionless.

\bar a - Length of the major axis, dimensionless.

If we know that \bar c = 5.2 and \bar a = 20.6, then the eccentricity of the ellipse is:

e = \frac{5.2}{20.6}

e = 0.252

The eccentricity of the ellipse is 0.252.

8 0
3 years ago
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