Answer:
A. Ein = 8.05*10^-4 V/m
B. Clockwise sense
Explanation:
A. the magnitude of the electric field induced in the ring is obtaind by using the following formula:
(1)
Ein: induced electric field
ds: differential of a path of the ring
ФB: magnetic flux in the ring
The Ein vector is parallel to ds in the complete ring. Furthermore, the area of the ring is constant, hence, you have in the equation (1):
(2)
dB/dt = -0.280T/s (it is decreasing)
A: area of the ring = π(r/2)^2= (π/4) r^2
r: radius of the ring = 4.60/2 = 2.30 cm
Then, you replace the values of all variables in the equation (2):

hence, the induced electric field is 8.05*10^-4 V/m
B. The induced current in the ring produced a magnetic field that is opposite to the magnetic field of the magnet. The, in this case you have that the induced current is in a clockwise sense.
The answer to the given question is lightning.
Lightning is most probably the deadliest aspect of a thunderstorm. It is <span> a sudden </span>electrostatic discharge<span> during an </span>electrical storm. It happens <span> when there is an electrostatic discharge between </span>electrically charged<span> regions of a </span>cloud, which is referred as the i<span>ntra-cloud lightning or IC, between that cloud and another cloud or the CC lightning, or between a cloud and the ground (CG lightning).</span>
Answer:
<h3>
a)</h3>




<u>=> R= 6 Ohms(Ω)</u>
<h3>b)</h3>

<em>these lights operate at the usual 240 volts direct from the main electricity supply. Therefore,</em>

<em>R and 100 can interchange places</em>


<u>=> R = 576 Ω</u>
<u></u>
By Ohm's Law:

=> 240 = I × 576
=>
=> I = 0.417 A
<h3 /><h3>c)</h3>
I don't know it's resistance,... so sorry
<h3>d)</h3>
The brightness of the bulb in series is <em><u>less than</u></em> when they're placed individually.
For bulbs in series their resistance gets added to form the equivalent resistance of the two bulbs.
Their resistances are nothing but mere numbers and the sum of two numbers(positive of course) is greater than the numbers.
So, the effective resistance of some bulbs in series <u>is more</u> than the individual resistance.
And
<em>Brightness, i. e., Power</em>

If resistance increases, Power decreases.
Here, the effective resistance was for sure larger, therefore resistance was increasing, hence power decreased taking brightness along with it.