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matrenka [14]
2 years ago
14

6. A ball kicked from ground level at an initial velocity of 60 m/s and an angle with ground

Physics
1 answer:
Oksana_A [137]2 years ago
3 0

Answer:

66.5 is the answer

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(II) A 20.0-kg box rests on a table. (a) What is the weight of the box and the normal force acting on it? (b) A 10.0-kg box is p
Bogdan [553]

*Fig is Attached with answer*

Answer:

(a)   Weight = Normal Force = 196.2 N

(b)   Normal force table on 20 kg box = 294.3 N

       Normal force 20 kg box on 10 kg box = 98.1 N

Explanation:

(a)   Mass = m = 20 kg                           g = 9.81 m/s²

      Weight = w = mg

                      w = 20 × 9.81

                      w = 196.2 N

As the box rests on the table so, normal force (NF) must be equal to the weight of the box.

                    NF = w = 196.2 N

(b)

m₁ = 20 kg                      m₂ = 10 kg

total mass = M = 30 kg

Total Weight = W = Mg  

                             = 30 × 9.81

                             = 294.3 N

As both the boxes rest on the table so, normal force (NF) must be equal to the total weight of the boxes.

                          NF = W = 294.3 N

Weight of 10 kg box = 10 × 9.81 = 98.1 N

As the 10 kg box is placed on the top of 20 kg box, So 20 kg box must exert a normal force that is equal to the weight of 10 kg box.

              Normal Force = Weight of 10 kg box = 98.1 N

6 0
3 years ago
Often in Physics we will show a frame of reference as a
OlgaM077 [116]

Answer:

In physics, a frame of reference, or reference frame, is a perspective that one uses to determine if an object is moving.

Explanation:

8 0
3 years ago
The volume of an object as a function of time calculated by V=At^3+B/t,where t is time measured in seconds and V is in cubic met
S_A_V [24]

Answer:

A = L^3 T^-3  ,  B = L^3 T

Explanation:

Given: volume ( V )  = At^3 + B/t  ------ ( 1 )

dimension of volume = L^3

and the Dimension of time = T

back to equation ( 1 )

L^3 = A * T^3   ------- ( 2 )

also L^3 = B/T ------- ( 3 )

from equation ( 2 )

A = L^3 T^-3

from equation ( 3 )

B = L^3 T

<u>The dimensions of the constants A and B </u>

A = L^3 T^-3  ,  B = L^3 T

8 0
3 years ago
A 79 kg person sits on a 3.7 kg chair. Each leg of the chair makes contact with the floor in a circle that is 1.3 cm in diameter
vampirchik [111]
I'll assume that the chair has four legs.

Since the chair weights 3.7 kg by itself, it will weigh (79+3.7)=82.7 kg with the person sitting on it. And each of the chair's legs will take about (82.7/4)=20.675 kg.

Each leg touches the floor in a circle with 1.3cm diameter. The area of that circle is about (3.14*(1.3/2)^2)=1.327 cm^2.

Pressure is measured by force per area. So, the pressure from each leg is about 20.675kg / 1.327cm^2. That simplifies to 15.58 kg/cm^2.
7 0
2 years ago
do u ever think that how are u living cause we could not even be here and God but made us but had did it all started I believe i
Katena32 [7]

Answer:

What is the question

Explanation:

lol

5 0
3 years ago
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