Question

A television of mass 12 kg sits on a table. The coefficient of static friction between the table and the television is 0.83. What is the minimum applied force that will cause the television to slide

Answer 1

The normal reaction between the television and the table is
N = 12 × 9.8 m/s² = 117.6 Newtons

But the static coefficient of friction is μ = 0.83

When the television is about to slide on the table, the applied force should overcome the force due to static friction;
Thus; the applied force should be at least 
F = μN
  = 0.83 × 117.6 N
  = 97.608 Newtons
Therefore; the minimum applied force will be 97.6 Newtons.

Answer 2

Answer:

98 N

Explanation:

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