Answer: The partial pressure of oxygen in the tank is 82.95 kPa.
Explanation:
According to Raoult's law, the partial pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the total pressure.
where,
= partial pressure of oxygen
= mole fraction of oxygen
= Total pressure
,
where = moles of oxygen =
= moles of Helium =
Thus the partial pressure of oxygen in the tank is 82.95 kPa.
Answer:
P₂ = 394.4 KPa
Explanation:
Given data:
Volume of gas = 152 dm³
Pressure of gas = 98.6 KPa
Final pressure = ?
Final volume = quartered = 1/4×152 = 38 dm³
Solution:
P₁V₁ = P₂V₂
P₂ = P₁V₁/V₂
P₂ = 98.6 KPa . 152 dm³ / 38 dm³
P₂ = 14987.2 KPa. dm³ / 38 dm³
P₂ = 394.4 KPa
We see the order with respect to crystal violet (m),but no longer the order with respect to hydroxide (n).
<h3>Concentration of hydroxide ion equation</h3>
Generally the equation for the chemical reaction is mathematically given as
(CV)+(aq) + (OH)-(aq) ------------>. CVOH(aq)
The rate law for the chemical reaction is given as
Rate = k[CV+]m[OH-]n,
Because the hydroxide ion conc is an extra of thousand times as massive as the conc of crystal violet, [OH–] will now not exchange drastically all through this experiment.
Therefore, you will find the order with respect to crystal violet (m),but no longer the order with admire to hydroxide (n).
For more information on Chemical Reaction
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