Answer:
<em>The empirical formula is Ag2O.</em>
<em>The empirical formula is Ag2O.Explanation:</em>
<em>The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.</em>
<em>The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.The ratio of atoms is the same as the ratio of moles. So our job is to calculate the molar ratio of Ag to </em><em>2</em><em>O.</em>
<em>do</em><em> </em><em>the</em><em> </em><em>steps</em><em> </em><em>.</em><em>.</em><em>.</em>
To get this into an integer ratio, we divide both numbers by the smaller value.
From this point on, I like to summarize the calculations in a table.
ElementAgMass/gXMolesXllRatiomllIntegers
mAgXXXm7.96Xm0.07377Xll2.00mmm2
mlOXXXXl0.59mm0.0369Xml1mmmml1
There are 2 mol of Ag for 1 mol of O.