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2 years ago

NEED HELP ASAP!!!

Physics

1 answer:

wolverine [178]2 years ago

8 0

Answer:

4. A 10-kilogram sled at rest

Explanation:

The object with most inertia is a 10-kilogram sled at rest.

Inertia is the tendency of a body to remain at rest or continue with uniform motion.

Now, this is better highlighted by Newton's first law of motion which states that "an object will remain in a state of rest or of uniform motion unless it is acted upon by an external force".

The more the mass of a body, the greater its inertia
So, the choice with the most mass will have the highest inertia and will be the most reluctant to change position.

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Suppose the tip of the minute hand of a clock is two inches from the center of the clock. Determine the distance traveled by the

sashaice [31]

1) The minute travels the circumference of a 4 inches circle is 60 minutes:

Circumference = 2πr = 2π(2in) = 4π in
Time = 60 minutes

2) Constant angular velocity => (4π / 60) = (x / 20) => x = 4π / 3 inches

x = 4.19 inches

Answer: 4.19 inches

4 0

3 years ago

A force is applied to an ideal spring (initially in its equilibrium position) and does 1.9 JJ of work stretching it 2.2 cmcm . H

Verdich [7]

Answer:

W=16.58J

Explanation:

initial information we have

work: $W=1.9J$

stretched distance: $x=2.2cm=0.022m$

from this, we can find the value of the constant of the spring k, with the equation for work in a spring:

$W=\frac{1}{2} kx^2$

substituting known values:

$1.9J=\frac{1}{2}k(0.022)^2\\$

and clearing for k:

$k=\frac{2(1.9J)}{0.022^2} \\k=7,851.24$

and now we want to know how much work is done when we stretch the spring a distance of 6.5cm from equilibrium, so now x is:

$x=6.5cm=0.065m$

and using the same formula for work, with the value of k that we just found:

$W=\frac{1}{2} kx^2$

$W=\frac{1}{2}(7851.24)(0.065)^2\\W=16.58J$

5 0

3 years ago

Read 2 more answers

True or False: There is no object that can travel faster than the speed of light.

Otrada [13]

True no object can travel faster than speed of light

6 0

2 years ago

A 2100 kg car starts from rest and accelerates at a rate of 2.6 m/s2 for 4.0 s. Assume that the force acting to accelerate the c

Reika [66]

When the system is experiencing a uniformly accelerated motion, there are a set of equations to work from. In this case, work is energy which consist solely of kinetic energy. That is, 1/2*m*v2. First, let's find the final velocity.

a = (vf - v0)/t
2.6 = (vf - 0)/4
vf = 10.4 m/s

Then W = 1/2*(2100 kg)*(10.4 m/s)2
W = 113568 J = 113.57 kJ

8 0

3 years ago

A child on a high dive has a mass of 40 kilograms. If the high dive is 10 meters in the air, what is the potential energy? GPE=m

saw5 [17]

Answer:

Ep = 3924 [J]

Explanation:

To calculate this value we must use the definition of potential energy which tells us that it is the product of mass by the acceleration of gravity by height.

$E_{p}=m*g*h\\$

where:

Ep = potential energy [J] (units of Joules)

m = mass = 40 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 10 [m]

$E_{p} =40*9.81*10\\E_{p} = 3924 [J]$

7 0

2 years ago