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LekaFEV [45]
3 years ago
11

he unknown solution is prepared by mixing CaCO3(s) and HCl(aq). The H2CO3 produced in this reaction decomposes to CO2 (g) and H2

O. Write the complete chemical equation for this reaction, indicating the state of each species. If ionic compounds dissociate, separate the ions in the equation.
Chemistry
1 answer:
inessss [21]3 years ago
8 0

Answer:

CaCO₃(s) + 2 H⁺(aq) + 2 Cl⁻(aq) ⇒ Ca²⁺(aq) + 2 Cl⁻(aq) + H₂O(l) + CO₂(g)

Explanation:

Let's consider the molecular equation that occurs when CaCO₃(s) reacts with HCl(aq).

CaCO₃(s) + 2 HCl(aq) ⇒ CaCl₂(aq) + H₂O(l) + CO₂(g)

The complete ionic equation includes all the ions and the compounds that do not dissociate in water.

CaCO₃(s) + 2 H⁺(aq) + 2 Cl⁻(aq) ⇒ Ca²⁺(aq) + 2 Cl⁻(aq) + H₂O(l) + CO₂(g)

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To standardize an H2SO4 solution, you put 20.00 mL of it in a flask with a few drops of indicator and put 0.450 M NaOH in a bure
hram777 [196]

To standardize 20.00 mL of 0.495 M H₂SO₄ are used 44.10 mL of 0.450 M NaOH in a neutralization reaction.

We want to standardize a H₂SO₄ solution with NaOH. The neutralization reaction is:

H₂SO₄ + 2 NaOH ⇒ Na₂SO₄ + H₂O

The buret, which contains NaOH, reads initially 0.63 mL, and 44.73 mL at the endpoint. The used volume of NaOH is:

V = 44.73 mL - 0.63 mL = 44.10 mL

44.10 mL of 0.450 M NaOH are used for the titration. The reacting moles of NaOH are:

0.04410 L \times \frac{0.450mol}{L} = 0.0198 mol

The molar ratio of H₂SO₄ to NaOH is 1:2. The moles of H₂SO₄ that react with 0.0198 moles of NaOH are:

0.0198 mol NaOH \times \frac{1molH_2SO_4}{2molNaOH} = 0.00990 molH_2SO_4

0.00990 moles of H₂SO₄ are in 20.00 mL of solution. The molarity of H₂SO₄ is:

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Learn more: brainly.com/question/2728613

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Answer:

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