Question

1. A body moving with uniform acceleration of 10 m/s2 covers a distance of 320 m. if its initial velocity was 60 m/s. Calculate its final velocity.​

Answer 1

Answer:

v² = u² + 2as

v² = 3600 + 6400

v² = 10000

v = 100

Explanation:

final velocity is 100 m/s

Answer 2

• initial velocity=u=60m/s
• Acceleration=10m/s^2=a
• Distance=s=320m
• Final velocity=v

According to third equation of kinematics

$\boxed{\sf v^2-u^2=2as}$

$\\ \sf\longmapsto v^2=u^2+2as$

$\\ \sf\longmapsto v^2=(60)^2+2(10)(320)$

$\\ \sf\longmapsto v^2=3600+3400$

$\\ \sf\longmapsto v^2=10000$

$\\ \sf\longmapsto v=\sqrt{10000}$

$\\ \sf\longmapsto v=100m/s$