The answer would be 1.25g
Since you have 10g of a substance, you would need to half your substance by doing this: 42/14=3
Once doing this you would half your substance 3 times like so:
10/2=5
5/2=2.5
2.5/2=1.25
An amorphous solid is defined as one lacking crystalline structure. Since it doesn’t have structure, it breaks to form a relatively random, jagged edges rather than straight ones it may tend to shatter in prices rather than cleave along a crystal plane l (since there is no crystal plane to break along)
Answer:
If the density is less than one, an object will float. If it is more than one, that object will sink.
Answer:
2.90×10¯⁴M
Explanation:
Step 1:
Data obtained from the question.
Equilibrium constant for the acid , Ka = 3.5×10^–8
concentration of the acetic acid, [CH3COOH] = 2.40M
Concentration of Hydrogen ion, [H+] =..?
Step 2:
The balanced equation for the reaction.
CH3COOH(aq) <=> H+(aq) + CH3COO-(aq)
Step 3:
Determination of the concentration of Hydrogen ion, [H+]. This can be obtained as follow:
Initial concentration:
[CH3COOH] = 2.40M
[H+] = 0
[CH3COO-] = 0
During reaction:
[CH3COOH] = –y
[H+] = +y
[CH3COO-] = +y
At Equilibrium:
[CH3COOH] = 2.40 –y
[H+] = y
[CH3COO-] = y
Now, we can obtain the concentration of Hydrogen ion, H+ as follow:
Ka = [H+] • [CH3COO-] /[CH3COOH]
3.5×10^–8 = y×y/2.40
Cross multiply
y² = 3.5×10^–8 × 2.40
Take the square root of both side
y = √(3.5×10^–8 × 2.40)
y = 2.90×10¯⁴
[H+] = y = 2.90×10¯⁴M
Therefore, the concentration of H+ at equilibrium is 2.90×10¯⁴M
During pyruvate processing , the two carbons from pyruvate combine with co-enzyme A . Pyruvate oxidation converts pyruvate (a three carbon molecules) into acetyl co A(a 2 carbon molecules) which it attach to co enzyme A to produce NADHN,A,D,H and also release one carbon dioxide molecules in the process.