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Nostrana [21]
3 years ago
8

Two football players move in a straight line directly toward one another. Their equations of motion are as follows:

Physics
1 answer:
iren [92.7K]3 years ago
6 0

The time when the two players will collide is 0.96 s.

The equation of motion of the two players is given as;

x1 = 0.1 m + (–3.9 m/s )t

x2 = –6.3 m + (2.8 m/s )t

The time when the two players collide, their displacement is equal or the difference in their position will be zero.

X_1 - X_2 = 0\\\\0.1 - 3.9 t - (-6.3 + 2.8t) = 0\\\\0.1 -3.9t + 6.3 -2.8t = 0\\\\6.4 -6.7t = 0\\\\6.7t = 6.4\\\\t = \frac{6.4}{6.7} = 0.96 \ s

Thus, the time when the two players will collide is 0.96 s.

Learn more here: brainly.com/question/18033352

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An Olympic runner completes the 200-meter sprint in 23 seconds. What is the runner’s average speed? (Round your answer to the
Amanda [17]

The average speed of the runner is 8.7m/s.

Therefore, Option C) 8.7m/s is the correct answer.

Given the data in the question;

Distance covered; d = 200m

Time taken; t = 23s

Average speed; s = \ ?

Speed is the rate at which an object covers a certain distance. It is expressed as:

s = \frac{d}{t}

Where s is speed, d is distance and t is time taken.

We substitute our given distance into the equation

s = \frac{200m}{23s} \\\\s = 8.6956m/s\\\\s = 8.7m/s

The average speed of the runner is 8.7m/s

Therefore, Option C) 8.7m/s is the correct answer.

Learn more: brainly.com/question/21503615

3 0
2 years ago
A 86 kg human stands on the surface of Venus. The mass of Venus is 4.9 × 1024 kg and its radius is 6.1 × 106 m. Collapse questio
iris [78.8K]

Answer:

755.37 N

Explanation:

We are given that

Mass of venus=m_1=4.9\times 10^{24}kg

Radius=r=6.1\times 10^6m

Mass of human=m_2=86 kg

We know that the gravitational force between two bodies

F=G\frac{m_1m_2}{r^2}

Where G=Gravitational constant=6.67\times 10^{-11}Nm^2/kg^2

Using the formula

The magnitude of the gravitational force exerted by Venus on the human=F=\frac{6.67\times 10^{-11}\times 86\times 4.9\times 10^{24}}{(6.1\times 10^6)^2}

The magnitude of the gravitational force exerted by Venus on the human=F=755.37N

7 0
3 years ago
Please help I don’t know the answer, I’m horrible in science
irga5000 [103]
I think it is C, I mean I tried sketching a graph hope it’s right
6 0
3 years ago
What is the change in internal energy (in J) of a system that releases 954 J of thermal energy to its surroundings and has 166 c
Harman [31]

Answer:

259.456 J

Explanation:

Given that,

Work done on the system = 166 cal

The systam releases 954 J of thermal energy to its surroundings

We need to find the change in internal energy. It can be given by using the first law of thermodynamics as follows :

\Delta U=Q-W

W = 166 cal = 694.544 (1cal = 4.184 J)

\Delta U=954-694.544\\\\=259.456\ J

So, the change in internal energy of the system is 259.456 J.

4 0
3 years ago
Consider an electron, of charge magnitude e = 1.602 10-19 C and mass me = 9.11 10-31 kg, moving in an electric field with an ele
Tems11 [23]

Answer: v= 7.509 x 10^6 m/s

B) the lower plate because the electron is negatively charged

Explanation:

From the question

Electronic charge (q) =1.602 x 10^-19c

Electric field intensity (E) = 8 x 10² = 800N/C

Mass of electron (m) = 9.11 x 10^-31 kg

Length of plate (L) = 50cm=0.5m

Distance between plates (D) = 20cm = 0.2m

Since the electron is entering a uniform electric field, the resulting motion will be of a constant acceleration and can be defined by the equations of motion with a constant acceleration.

From newton's law of motion.

F= ma

The force (F) is coming from the electric field which is

F=Eq.

Thus F = 800 x 1.602 x 10^-19

F = 1.2816 x 10^-16 N

Acceleration of electron (a) = F/m where m is the mass of electron (given above)

Hence

a = 1.2816 x 10^-16 / 9.11 x 10^-31

a= 1.41 x 10¹⁴ m/s².

Using Newton laws of motion to get velocity, we recall that v²= u² + 2ad

Where v is final velocity, u is initial velocity (zero in this case because the electron starts it motion from rest), a= acceleration, d= distance traveled (which in this case is distance between plates)

v² = 0² + 2(1.41 x 10¹⁴) x 0.2

v² = 5.64 x 10¹³

Thus v = √ 5.64 x 10¹³

v = 7.509 x 10^6 m/s

Since the electric field is upwards it denotes that the positive plate is downward and the negative is upward ( this is because electric flux from a positive charge has an outward flow and that from a negative charge has an inward flow. So from our questions, if the electric field is upward, it means it is starting from the bottom plate which will be positive) the electron (which is negatively charged) will be attracted to the positive plate which is downward for this question of ours.

So therefore, the electron is attracted to the downward plate because it (electron) is negative

Option B

4 0
4 years ago
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