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AlexFokin [52]
2 years ago
15

Why might it be important to identify isoelectronic ions/atoms?

Chemistry
1 answer:
polet [3.4K]2 years ago
5 0

Answer:

Isoelectronicity may be used to predict the properties and reactions of a species. It is used to identify hydrogen-like atoms, which have one valence electron and are thus isoelectronic to hydrogen.

Explanation:

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Which element has chemical properties that are most<br> similar to potassium, And why?
bekas [8.4K]

Answer:

Brainliest pls

Explanation:

The components potassium and sodium have comparable substance properties since they have a similar number of valence electrons

8 0
2 years ago
A pure substance made up of molecules of the same kind of atoms is called...
slava [35]

Answer:

All substances that are  made up of the same kind of mole ules are called pure substances.

So what do you mean ?

Explanation:

5 0
3 years ago
Read 2 more answers
Name a molecule that is small enough to enter the cell
Oksanka [162]

Answer:

oxygen molecule

Explanation:

I belive it is oxygen molecule

8 0
3 years ago
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You find a compound composed only of element "X" and hydrogen, and know that it is 91.26% element X by mass. Each molecule has 2
worty [1.4K]
Since you know the ratio of atoms, you can start to put a formula togeter. The formula might look like:<span>
X<span>H2.67 
</span></span>but since atoms can't come in fractional amounts, we have to multiply the formula by some number in order to turn 2.67 into a whole #, while still maintaining the ratio. Multiplying 2.67 by 3 yields 8, so the most likely ratio in the molecule is

X3H8<span>so the ratio of 1:2.67 is still maintained. The mass percent tells you that out of every 100g of compound, 91.26g is element X, so the other 8.74g must be H. Dividing each mass by the number of moles in the formula gets us the molar mass of each element (approximately). DIviding 8.74g by 8 gets 1.09, roughly the molar mass of hydrogen. Dividing 91.26g by 3 gets us 30.4, roughly the molar mass of phosphorus. Element X is most likely phosphorus</span>
4 0
3 years ago
Read 2 more answers
Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of
bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol..[1]

O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol..[2]

NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol..[3]

NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}

2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol

2\times \Delta H^o_{4}=470.3 kJ/mol

\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0
3 years ago
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