Explanation:
h=((usinx)^2)/2g
12.7=((usin(19))^2)/(2×9.8)
(12.7×2×9.8)=(usin(19))^2
248.92=(usin(19))^2
usin19 =√248.92 =15.78
U =15.78/(sin19)
=48.46m/s----> speed
Answer: North
Explanation: I believe the friction will go the opposite way of the object being pushed.
Water cycle, evaporation, condensation, and freezing
Answer:
T = 764.41 N
Explanation:
In this case the tension of the string is determined by the centripetal force. The formula to calculate the centripetal force is given by:
(1)
m: mass object = 2.3 kg
r: radius of the circular orbit = 0.034 m
v: tangential speed of the object
However, it is necessary to calculate the velocity v first. To find v you use the formula for the kinetic energy:
![K=\frac{1}{2}mv^2](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
You have the value of the kinetic energy (13.0 J), then, you replace the values of K and m, and solve for v^2:
![v^2=\frac{2K}{m}=\frac{2(13.0J)}{2.3kg}=11.3\frac{m^2}{s^2}](https://tex.z-dn.net/?f=v%5E2%3D%5Cfrac%7B2K%7D%7Bm%7D%3D%5Cfrac%7B2%2813.0J%29%7D%7B2.3kg%7D%3D11.3%5Cfrac%7Bm%5E2%7D%7Bs%5E2%7D)
you replace this value of v in the equation (1). Also, you replace the values of r and m:
![F_c=(2.3kg)(\frac{11.3m^2/s^2}{0.034})=764.41N](https://tex.z-dn.net/?f=F_c%3D%282.3kg%29%28%5Cfrac%7B11.3m%5E2%2Fs%5E2%7D%7B0.034%7D%29%3D764.41N)
hence, the tension in the string must be T = Fc = 764.41 N
Answer:
4 m/s
Explanation:
T = Tension
m = Mass of string
Velocity of wave in string is given by
For first cable
![v_1=\sqrt{\dfrac{T}{m}}=8](https://tex.z-dn.net/?f=v_1%3D%5Csqrt%7B%5Cdfrac%7BT%7D%7Bm%7D%7D%3D8)
For second cable
![v_2=\sqrt{\dfrac{T}{4m}}\\\Rightarrow v_2=\dfrac{1}{2}\sqrt{\dfrac{T}{m}}\\\Rightarrow v_2=\dfrac{1}{2}\times 8\\\Rightarrow v_2=4\ m/s](https://tex.z-dn.net/?f=v_2%3D%5Csqrt%7B%5Cdfrac%7BT%7D%7B4m%7D%7D%5C%5C%5CRightarrow%20v_2%3D%5Cdfrac%7B1%7D%7B2%7D%5Csqrt%7B%5Cdfrac%7BT%7D%7Bm%7D%7D%5C%5C%5CRightarrow%20v_2%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%208%5C%5C%5CRightarrow%20v_2%3D4%5C%20m%2Fs)
The speed of wave in cable two is 4 m/s