All categories

2 years ago

If Bromine belongs to the group halogens in group 7a, what do you know about the

Chemistry

1 answer:

Mama L [17]2 years ago

7 0

Answer:

it has 7 electrons and it react to the elements with only 1 valence electron, which are elements in group 1

Explanation:

You might be interested in

6.) 50.0 mol H2O ? molecules

8_murik_8 [283]

<h3>Answer:</h3>

3.01 × 10²⁵ molecules H₂O

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<h3>Explanation:</h3>

Step 1: Define

50.0 mol H₂O

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

$\displaystyle 50.0 \ mol \ H_2O(\frac{6.022 \cdot 10^{23} \ molecules \ H_2O}{1 \ mol \ H_2O} )$ = 3.011 × 10²⁵ molecules H₂O

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

3.011 × 10²⁵ molecules H₂O ≈ 3.01 × 10²⁵ molecules H₂O

5 0

2 years ago

The law of universal gravitation describes the gravitational force between two objects.

Sliva [168]

Answer:

mass and distance

Explanation:

The strength of this force depends on the mass

of each object and

the distance

between them.

6 0

2 years ago

32.33 mL of 1.031 M potassium hydroxide were required to reach the endpoint of a titration of 50.00 mL of nitric acid. What was

tester [92]

The molar concentration of the nitric acid solution was 0.6666 mol/L.

Balanced equation: KOH + HNO_3 → KNO_3 + H_2O

Moles of KOH: 32.33 mL KOH × (1.031 mmol KOH /1 mL KOH)

= 33.33 mmol KOH

Moles of HNO_3: 33.33 mmol KOH× (1 mmol HNO_3/1 mmol KOH)

= 33.33 mmol HNO_3

Concentration of KOH: c = "moles"/"litres" = 33.33 mmol/50.00 mL

= 0.6666 mol/L

4 0

3 years ago

1) *

Marizza181 [45]

i think i am sorry if am wrong

8 0

3 years ago

Which of these is connected by three covalent bonds?

leonid [27]

Answer:

NH3

I GUESS

HOPE THIS HELPS U

6 0

2 years ago