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2 years ago

11

A motor whose pulley is 80mm in diameter is rotating at 30 revolutions per minute and is connected by a belt to another pulley o

f 40mm diameter, calculate the rotating speed of the smaller pulley

1 answer:

Firdavs [7]2 years ago

8 0

Answer:

169

Explanation:

ye men thats the answer

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Your program should read from an input file, which will contain one or more test cases. Each test case consists of one line cont

Aliun [14]

Answer:

#include <bits/stdc++.h>

using namespace std;

struct cell

{

int x, y;

int dis;

cell() {}

cell(int x, int y, int dis) : x(x), y(y), dis(dis) {}

};

bool isInside(int x, int y, int N)

{

if (x >= 1 && x <= N && y >= 1 && y <= N)

return true;

return false;

}

int minStepToReachTarget(int knightPos[], int targetPos[],

int N)

{

int dx[] = {-2, -1, 1, 2, -2, -1, 1, 2};

int dy[] = {-1, -2, -2, -1, 1, 2, 2, 1};

queue<cell> q;

q.push(cell(knightPos[0], knightPos[1], 0));

cell t;

int x, y;

bool visit[N + 1][N + 1];

for (int i = 1; i <= N; i++)

for (int j = 1; j <= N; j++)

visit[i][j] = false;

visit[knightPos[0]][knightPos[1]] = true;

while (!q.empty())

{

t = q.front();

q.pop();

visit[t.x][t.y] = true;

if (t.x == targetPos[0] && t.y == targetPos[1])

return t.dis;

for (int i = 0; i < 8; i++)

{

x = t.x + dx[i];

y = t.y + dy[i];

if (isInside(x, y, N) && !visit[x][y])

q.push(cell(x, y, t.dis + 1));

}

}

}

int main(){

ifstream obj("input.txt");

string line;

int x1,y1,x2,y2;

while(getline(obj,line)){

//cout<<line<<endl;

x1=line[0]-'a'+1;

y1=line[1]-'0';

x2=line[3]-'a'+1;

y2=line[4]-'0';

int N = 8;

int knightPos[] = {x1,y1};

int targetPos[] = {x2,y2};

cout <<"To get from "<<line[0]<<line[1]<<" to "<<line[3]<<line[4]<<" takes "<< minStepToReachTarget(knightPos, targetPos, N)<<" Knight Moves."<<endl;

}

return 0;

}

3 0

3 years ago

An exit sign must be:Colored in a way that doesn’t attract attentionIlluminated by a reliable light sourceAt least 3 inches tall

Ksenya-84 [330]

Answer:

Red

Explanation:

5 0

3 years ago

In fully developed laminar flow in a circular pipe the velocity at R/2 (mid-way between the wall surface and the centerline) is

Butoxors [25]

Answer:

$u_{max} = 17.334\,\frac{m}{s}$

Explanation:

Let consider that velocity profile inside the circular pipe is:

$u(r) = 2\cdot U_{avg} \cdot \left(1 - \frac{r^{2}}{R^{2}} \right)$

The average speed at $r = \frac{1}{2} \cdot R$ is:

$U_{avg} = \frac{13\,\frac{m}{s} }{2\cdot \left(1-\frac{1}{4} \right)}$

$U_{avg} = 8.667\,\frac{m}{s}$

The velocity at the center of the pipe is:

$u_{max} = 2\cdot U_{avg}$

$u_{max} = 17.334\,\frac{m}{s}$

6 0

2 years ago

Read 2 more answers

2.11 Consider a 400 mm × 400 mm window in an aircraft. For a temperature difference of 90°C from the inner to the outer surface

alexandr402 [8]

Answer:

The heat loss rate through one of the windows made of polycarbonate is 252W. If the window is made of aerogel, the heat loss rate is 16.8W. If the window is made of soda-lime glass, the heat loss rate is 1190.4W.

The cost associated with the heat loss through the windows for an 8-hour flight is:

For aerogel windows: $17.472 (most efficient)

For polycarbonate windows: $262.08

For soda-lime glass windows: $1,238.016 (least efficient)

Explanation:

To calculate the heat loss rate through the window, we can use a model of heat transmission by conduction throw flat wall. Using unidimensional Fourier law:

$\frac{dQ}{dt}=\dot Q =-kS\nabla \vec{T}$

In this case:

$\dot Q =k\frac{S}{L} \Delta T$

If we replace the data provided by the problem we get the heat loss rate through one of the windows of each material (we only have to change the thermal conductivities).

To obtain the thermal conductivity of the soda-lime glass we use the graphic attached to this answer (In this case for soda-lime glass k₃₀₀=0.992w/m·K).

To calculate the cost associated with the heat loss through the windows for an 8-hour flight we use this formula (using the heat loss rate calculated in each case):

$Cost=C_{hc}\cdot \dot Q \cdot t \cdot n=1\frac{\$}{Kwh} \cdot \dot Q \cdot 8h \cdot 130$

6 0

2 years ago

The kinetic energy correction factor depends on the (shape — volume - mass) of the cross section Of the pipe and the (velocity —

butalik [34]

Answer:

The kinetic energy correction factor the depends on the shape of the cross section of the pipe and the velocity distribution.

Explanation:

The kinetic energy correction factor take into account that the velocity distribution over the pipe cross section is not uniform. In that case, neither the pressure nor the temperature are involving and as we can notice, the velocity distribution depends only on the shape of the cross section.

3 0

3 years ago