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DiKsa [7]
3 years ago
15

Extremely large main sequence stars consume their fuel quickly and burn hot and bright. As they consume all their hydrogen, they

become supergiants. Describe the changes that take place, in terms of luminosity and temperature, to these large main sequence stars as they exhaust their hydrogen supplies.
Physics
1 answer:
beks73 [17]3 years ago
3 0

Answer:  Their temperature decreases dramatically, but their luminosity increases only slightly.

Explanation: Edmentum answer

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A particular car can go from rest to 90 km/h in 10 s. What is its acceleration? (Report your answer in km/h*s)
Romashka-Z-Leto [24]

Answer: 9 km/h

Explanation:i’m pretty sure

5 0
4 years ago
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A 1.0-cm-diameter pipe widens to 2.0, then narrows to 0.5. Liquid flows through the first segment at a speed of 4.0. What is the
uysha [10]

Answer:

3.14 ×  10⁻⁴  m³  /s

Explanation:

The flow rate (Q) of a fluid is passing through different cross-sections remains of pipe always remains the same.

Q = Area x velocity

Given:

Diameters of 3 sections of the pipe are given as  

d1  =  1.0  cm,  d2  =  2.0  cm  and  d3  =  0.5  cm.

Speed in the first segment of the pipe is  

v1  =  4  m/s.

From the equation of continuity the flow rate through different cross-sections remains the same.

Flow  rate  =  Q  =  A1  v1  =  A2  v2  =  A3  v3.

Q = A1v1

   =π/4  d²1  v1  =  π/4  * 0.01² ×4.0 m³/s  =  3.14 ×  10⁻⁴  m³  /s

3 0
3 years ago
A piano tuner is using a 392 Hz tuning fork to tune the wire for a G-Natural note. She hears 4 beats per second. What are the tw
inysia [295]

A beat is an interference pattern between two sounds of slightly different frequencies, perceived as a periodic variation in volume whose rate is the difference of the two frequencies. Frequency beat is equal to,

f_{beat} =| f_2\pm f_1 |

The reference frequency in our case would be 392Hz, and since there is the possibility of the upper and lower range for the amount of beats per second that the two possible frequencies are heard would be

f_{beat} =|392+4|= 396Hz

f_{beat} =|392-4|=388Hz

Therefore the two possible frequencies the piano wire is vibrating at, would be 396Hz and 388Hz

5 0
3 years ago
Three charges, each of magnitude 10 nC, are at separate corners of a square of edge length 3 cm. The two charges at opposite cor
FinnZ [79.3K]

Answer:

The force exerted by three charges on the fourth is F_{resultant}=2.74\times10^{-5}\ \rm N

Explanation:

Given:

  • The magnitude of three identical charges, q=10\ \rm nC
  • Length of the edge of the square a=3 cm
  • Magnitude of fourth charge ,Q=3 nC

According to coulombs Law the force F between any two charge particles is given by

F=\dfrac{kQq}{r^2}

where r is the radial distance between them.

Since the force acting on the charge particle will be in different directions so according to triangle law of vector addition

F_{resultant}=\sqrt ((\dfrac{kQq}{L^2})^2+(\dfrac{kQq}{L^2} })^2)+\dfrac{kQq}{(\sqrt{2}L)^2}\\F_{resultant}=\dfrac{kQq}{L^2}(\sqrt{2}-\dfrac{1}{2})\\F_{resultant}=\dfrac{9\times10^9\times10\times10^{-10}\times3\times10^{-9}}{0.03^2}(\sqrt{2}-\dfrac{1}{2})\\F_{resultant}=2.74\times 10^{-5}\ \rm N

5 0
3 years ago
If a radio wave carries information by changing the amplitude of the transmitted wave, what kind of broadcast might it possibly
mariarad [96]
Option A because those are the correct ones
4 0
2 years ago
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