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Mkey [24]
2 years ago
12

What is the correct answer?

Physics
1 answer:
LUCKY_DIMON [66]2 years ago
8 0

Answer:

I think is d and you or very pretty

Explanation:

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the hot gas lines need to be insulated? A never B always C if they are exposed to cold temperatures that could cause the refrige
muminat
The answer is a because it never needs to be insulated
8 0
2 years ago
Does a generator start a Direct Current?
lesya [120]
A direct-current (DC) generator is a rotating machine that supplies an electrical output with unidirectional voltage and current. ... The field is produced by direct current in field coils or by permanent magnets on the stator. The output, or armature, windings are placed in slots in the cylindrical iron rotor.
3 0
3 years ago
How long will it take a ball to roll 10 meters along the floor at a speed of 0.5 m/s?
IRINA_888 [86]

Answer:

20 seconds.

Explanation:

The following data were obtained from the question:

Distance = 10 m

Speed = 0.5 m/s

Time =...?

The speed of an object is simply defined as the distance travelled by the object per unit time. Mathematically, it is expressed as:

Speed = Distance /time

With the above formula, we can obtain the time taken for the ball to travel a distance of 10 m as shown below:

Distance = 10 m

Speed = 0.5 m/s

Time =...?

Speed = Distance /time

0.5 = 10/time

Cross multiply

0.5 × time = 10

Divide both side by 0.5

Time = 10/0.5

Time = 20 secs.

Therefore, it will take 20 seconds for the ball to travel a distance of 10 m.

6 0
3 years ago
Use cylindrical coordinates. Evaluate E (x − y) dV, where E is the solid that lies between the cylinders x2 + y2 = 1 and x2 + y2
S_A_V [24]

Answer:hchv nhgjj

Explanation:

ggchh

3 0
3 years ago
Like the filters falling through the air, a car on the freeway represents an object with a high Reynolds number traveling throug
Goshia [24]

Answer:

ΔF=125.22 %

Explanation:

We know that drag force on the car given as

F_D=\dfrac{1}{2}\rho C_DA v^2

C_D=Drag coefficient

A=Projected area

v=Velocity

ρ=Density

All other quantity are constant so we can say that drag force and velocity can be given as

\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}

Now by putting the values

\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}

\dfrac{F_D_1}{F_D_2}=\dfrac{50^2}{75^2}

\dfrac{F_D_1}{F_D_2}=0.444

Percentage Change in the drag force

\Delta F=\dfrac{F_D_2-F_D_1}{F_D_1}\times 100

\Delta F=\dfrac{F_D_2-0.444F_D_2}{0.444F_D_2}\times 100

\Delta F=\dfrac{1-0.444}{0.444}\times 100

ΔF=125.22 %

Therefore force will increase by 125.22  %.

3 0
3 years ago
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