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kari74 [83]
3 years ago
6

Pls help!!Thanks =] ​

Physics
2 answers:
lbvjy [14]3 years ago
4 0

Answer:

i think 2 N right because the wheels have a bigger force so we will subtract both sides which is 2 and right is longer so its 2 N Right?

lidiya [134]3 years ago
4 0

Answer:

2N right

Explanation:

5-3= 2

5 N to the right and 3 N to the left

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Which of the following is not a component of a normal experiment?
MaRussiya [10]

Answer:

D. Validity group

Explanation:

A validity group is not necessarily a component of a normal experiment.

A normal experiment is made up of the dependent variables, independent variables, and most times the control group.

  • The dependent variable is one that relies on the outcome of the effect produced from the experimental design
  • The independent variable is the one that causes a desired effect under the study.
  • The control group is a group that does not receive any treatment nor attenuation of the conditions.
4 0
3 years ago
Consider a roller coaster begins 15m above the ground. If the cart has a mass of 75kg, what is the velocity of the cart halfway
SashulF [63]

Answer:

v = 12.12 m/s

Explanation:

Given that,

The mass of the cart, m = 75 kg

The roller coaster begins 15 m above the ground.

We need to find the velocity of the cart halfway to the ground. Let the velocity be v. Using the conservation of energy at this position, h = 15/2 = 7.5 m

mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 7.5} \\\\v=12.12\ m/s

So, the velocity of the cart is 12.12 m/s.

7 0
3 years ago
What's a sentence using work in a nonscientific sense
kvv77 [185]

My Physics teacher keeps giving us way too much work to do at home.

7 0
4 years ago
Read 2 more answers
A mass is oscillating with amplitude A at the end of a spring.
Dmitry_Shevchenko [17]

A) x=\pm \frac{A}{2\sqrt{2}}

The total energy of the system is equal to the maximum elastic potential energy, that is achieved when the displacement is equal to the amplitude (x=A):

E=\frac{1}{2}kA^2 (1)

where k is the spring constant.

The total energy, which is conserved, at any other point of the motion is the sum of elastic potential energy and kinetic energy:

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 (2)

where x is the displacement, m the mass, and v the speed.

We want to know the displacement x at which the elastic potential energy is 1/3 of the kinetic energy:

U=\frac{1}{3}K

Using (2) we can rewrite this as

U=\frac{1}{3}(E-U)=\frac{1}{3}E-\frac{1}{3}U\\U=\frac{E}{4}

And using (1), we find

U=\frac{E}{4}=\frac{\frac{1}{2}kA^2}{4}=\frac{1}{8}kA^2

Substituting U=\frac{1}{2}kx^2 into the last equation, we find the value of x:

\frac{1}{2}kx^2=\frac{1}{8}kA^2\\x=\pm \frac{A}{2\sqrt{2}}

B) x=\pm \frac{3}{\sqrt{10}}A

In this case, the kinetic energy is 1/10 of the total energy:

K=\frac{1}{10}E

Since we have

K=E-U

we can write

E-U=\frac{1}{10}E\\U=\frac{9}{10}E

And so we find:

\frac{1}{2}kx^2 = \frac{9}{10}(\frac{1}{2}kA^2)=\frac{9}{20}kA^2\\x^2 = \frac{9}{10}A^2\\x=\pm \frac{3}{\sqrt{10}}A

3 0
3 years ago
What happens to the magnetic domains in a material when the material is placed in a strong magnetic field?
Allisa [31]
If it is diamagnetic then it magnetise opposite to magnetic field
if paramagnetic it weekly magnetise in direction of magnetic field
if ferromagnetic it strongly magnetise in direction of magnetic field
6 0
3 years ago
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