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alexira [117]
3 years ago
15

What force controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped i

n clusters?
Physics
1 answer:
JulijaS [17]3 years ago
4 0

Answer:

Gravity.

Explanation:

The force that controls the movement of the planets around the sun, holds together stars grouped in galaxies, and galaxies grouped in clusters is called gravity.

This ultimately implies that, gravity is considered to be a universal force of attraction that acts between all objects that has both mass, energy and occupy space. Therefore, it acts in such a way as to bring objects together.

Additionally, the gravity of earth makes it possible for all physical objects to possess weight.

Weight can be defined as the force acting on a body or an object as a result of gravity.

Mathematically, weight is given by the formula;

Weight = mg

Where;

m is the mass of an object.

g is acceleration due to gravity.

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Answer: The correct answer is graph A.

Explanation:

See Khan Academy.

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Help in my home work!<br>convert 80°c to fahrenheit?​
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176 degrees fahrenheit

Explanation:

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2 years ago
What investigations allow for the control of variables
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How long should a spring be stretched for it to store 45 J of energy? The force constant of the spring is
ELEN [110]

Answer:

x = 0.4 m

Explanation:

When a spring is stretched from its equilibrium position. Some energy is stored in the spring. This energy is called the elastic potential energy of the spring. The formula used to calculate the magnitude of this stored energy is given as follows:

P.E = (1/2)kx²

where,

P.E = Elastic Potential Energy Stored in the spring = 45 J

k = Spring Constant = 540 N/m

x = amount of stretching = ?

Therefore,

45 J = (1/2)(540 N/m)x²

x² = (45 J)(2)/(540 N/m)

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<u>x = 0.4 m</u>

5 0
3 years ago
A projectile enters a resisting medium at x = 0 with an initial velocity v0 = 910 ft/s and travels 5 in. before coming to rest.
evablogger [386]

Answer:

a = - 1.987 × 10⁶ ft/s²

t = 6.84 × 10⁻⁴ s

Explanation:

v₀ = 910 ft/s

x = 5 in.

relation v = v₀ - k x

v = 0 as body comes to rest

0 = 900 - 5k/12

k = 2184 s⁻¹

acceleration

\frac{\mathrm{d} v}{\mathrm{d} t} = -k\frac{\mathrm{d} x}{\mathrm{d} t}

where

(A) a = -k × v

 at v= 910 ft/s

     a = - 1.987 × 10⁶ ft/s²

(B)  at x = 3.9 in.

v = 910 - 3.9(2184)/12

v = 200.2 m/s

\frac{\mathrm{d} v}{\mathrm{d} t} = -k\frac{\mathrm{d} x}{\mathrm{d} t}

\frac{dv}{v} = -kdt

\int\limits^{200.2}_{900} {\frac{1}{v} }dv = -k\int\limits^t_0 dt

ln(200.2)-ln(900) = -kt

t = 6.84 × 10⁻⁴ s

3 0
3 years ago
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