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Brut [27]
2 years ago
6

Consider a 0.70 M solution of HOCl. If the molarity was decreased to 0.3 M, what would happen to the percent dissociation?

Chemistry
1 answer:
melomori [17]2 years ago
5 0

Answer:

The percent dissociation would increase

Explanation:

Percent dissociation is the ratio of amount dissociated to the initial concentration.

Decreasing the concentration of the solution leads to an increase in percent dissociation.

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velikii [3]

Answer: The [OH^-] of a solution is 10^{-12} M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

moles of HCl = \frac{\text {given mass}}{\text {Molar mass}}=\frac{0.0912g}{36.5g/mol}=0.0025mol

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.0025\times 1000}{250}=0.01

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1 mole of HCl gives 1 mole of H^+

Thus 0.01 moles of HCl gives =\frac{1}{1}\times 0.01=0.01 moles of H^+

Putting in the values:

[H^+][OH^-]=10^{-14}

[0.01][OH^-]=10^{-14}

[OH^-]=10^{-12}

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8 0
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