Explanation:
Given that,
Distance covered, d = 32 m
Time, t = 8.7 m
Final speed of the truck, v = 2.1 m/s
(a) Let a is the acceleration and u is the original speed of the truck.
Using first equation of kinematics as :

..............(1)
Using second equation of kinematics as :

...........(2)
On solving equation (1) and (2) we get :
Original speed, 
(b) Acceleration, 
Hence, this is the required solution.
Answer:
The coefficient of static friction is : 0.36397
Explanation:
When we have a box on a ramp of angle
, and the box is not sliding because of friction, one analyses the acting forces in a coordinate system system with an axis parallel to the incline.
In such system, the force of gravity acting down the incline is the product of the box's weight times the sine of the angle:

Recall as well that component of the box's weight that contributes to the Normal N (component perpendicular to the ramp) is given by:

and the force of static friction (f) is given as the static coefficient of friction (
) times the normal N:

When the box starts to move, we have that the force of static friction equals this component of the gravity force along the ramp:

Now we use this last equation to solve for the coefficient of static friction, recalling that the angle at which the box starts moving is 20 degrees:

A) Measure the pH of different household chemicals
Explanation:
To demonstrate a chemical property using an experiment, measuring the pH of different household chemicals will be the best way. The pH is the degree of hydrogen or hydroxyl ion concentration in a solution.
- Chemical properties tell us about what a substance can do.
- It shows if a substance will react with other substances or not.
- Examples are flammability, rusting of iron, precipitation, decomposition of water by electric current e.t.c.
- Measuring the pH is a chemical property determination procedure.
- The pH points to the degree of acidity or alkalinity of a solution.
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The resonant frequency of a circuit is the frequency
at which the equivalent impedance of a circuit is purely real (the imaginary part is null).
Mathematically this frequency is described as

Where
L = Inductance
C = Capacitance
Our values are given as


Replacing we have,



From this relationship we can also appreciate that the resonance frequency infers the maximum related transfer in the system and that therefore given an input a maximum output is obtained.
For this particular case, the smaller the capacitance and inductance values, the higher the frequency obtained is likely to be.
Neither analog nor digital