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BigorU [14]
3 years ago
10

The information below describes a redox reaction. 3 equations: First: upper C r superscript 3 plus (a q) plus 2 upper C l supers

cript minus (a q) right arrow upper C r (s) plus upper C l subscript 2 (g). Second: 2 upper C l superscript minus (a q) right arrow upper C l subscript 2 (g) plus 2 e superscript minus. Third: upper Cr superscript 3 plus (a q) plus 3 e superscript minus right arrow upper C r (s). What is the final, balanced equation for this reaction? 2 upper C r superscript 3 plus (a q) plus 6 upper C l superscript minus (a q) right arrow 2 upper C r (s) plus 3 upper C l subscript 2 (g). 2 upper C r superscript 3 plus (a q) plus 2 upper C l superscript minus (a q) plus 6 e superscript minus right arrow upper C l subscript 2 (g) plus 2 upper C r (s). Upper C r superscript 3 plus (a q) plus 6 upper C l superscript minus (a q) plus 3 e superscript minus right arrow 2 upper r (s) plus 3 upper C l subscript 2 (g). Upper C r superscript 3 plus (a q) plus 2 upper C l superscript minus (a q) right arrow upper C r (s) plus upper C l subscript 2 (g).
Chemistry
1 answer:
Marrrta [24]3 years ago
7 0

Answer:

A.

Explanation:

I just took the quiz.

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Answer:

Butanoic acid present in solution

Explanation:

In this case, we have a buffer solution of butanoic acid and sodium butanoate.  In other words a reaction like this:

HC₄H₇O₂ + H₂O <------> C₄H₇O₂⁻ + H₃O⁺   Ka = 1.5x10⁻⁵

The low value of Ka means that this is a weak acid. So, after this, the NaOH is added to the solution.

The NaOH is a really strong base, so we might expect that the pH of the solution increase drastically, however this do not occur.

The reason for this is because the first thing to happen in this reaction is an acid base reaction.

The NaOH react with the butanoic acid still present in solution, because is a weak acid, so in solution, this acid is not completely dissociated into it's respective ions. So the butanoic acid reacts with the NaOH and the products:

HC₄H₇O₂ + NaOH <------> Na⁺C₄H₇O₂⁻ + H₂O

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Answer:

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