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Slav-nsk [51]
3 years ago
11

...hhheeelppppppppppp meeeee​

Physics
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

RESISTANCE

Explanation:

A multimeter or multitester is a measuring instrument that can measure multiple electrical properties. A typical multimeter can measure voltage, resistance, and current, in which case it is also known as a volt-ohm-milliammeter.

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Calculate the magnitude of the linear momentum for the following cases.
svet-max [94.6K]

Answer:

8.4335 x 10^-²¹, 1.78204 x 10²⁶

Explanation:

p = mv

p = (5.05 x 10⁶)(1.67 x 10^-²⁷)

p = 8.4335 x 10^-²¹

p = mv

p = (5.98 x 10²⁴)(2.98 x 10)

p = 1.78204 x 10²⁶

4 0
2 years ago
Three masses (3 kg, 5 kg, and 7 kg) are located in the xy-plane at the origin, (2.3 m, 0), and (0, 1.5 m), respectively.
Artist 52 [7]

Answer:

a) C.M =(\bar x, \bar y)=(0.767,0.7)m

b) (x_4,y_4)=(-1.917,-1.75)m

Explanation:

The center of mass "represent the unique point in an object or system which can be used to describe the system's response to external forces and torques"

The center of mass on a two dimensional plane is defined with the following formulas:

\bar x =\frac{\sum_{i=1}^N m_i x_i}{M}

\bar y =\frac{\sum_{i=1}^N m_i y_i}{M}

Where M represent the sum of all the masses on the system.

And the center of mass C.M =(\bar x, \bar y)

Part a

m_1= 3 kg, m_2=5kg,m_3=7kg represent the masses.

(x_1,y_1)=(0,0),(x_2,y_2)=(2.3,0),(x_3,y_3)=(0,1.5) represent the coordinates for the masses with the units on meters.

So we have everything in order to find the center of mass, if we begin with the x coordinate we have:

\bar x =\frac{(3kg*0m)+(5kg*2.3m)+(7kg*0m)}{3kg+5kg+7kg}=0.767m

\bar y =\frac{(3kg*0m)+(5kg*0m)+(7kg*1.5m)}{3kg+5kg+7kg}=0.7m

C.M =(\bar x, \bar y)=(0.767,0.7)m

Part b

For this case we have an additional mass m_4=6kg and we know that the resulting new center of mass it at the origin C.M =(\bar x, \bar y)=(0,0)m and we want to find the location for this new particle. Let the coordinates for this new particle given by (a,b)

\bar x =\frac{(3kg*0m)+(5kg*2.3m)+(7kg*0m)+(6kg*a)}{3kg+5kg+7kg+6kg}=0m

If we solve for a we got:

(3kg*0m)+(5kg*2.3m)+(7kg*0m)+(6kg*a)=0

a=-\frac{(5kg*2.3m)}{6kg}=-1.917m

\bar y =\frac{(3kg*0m)+(5kg*0m)+(7kg*1.5m)+(6kg*b)}{3kg+5kg+7kg+6kg}=0m

(3kg*0m)+(5kg*0m)+(7kg*1.5m)+(6kg*b)=0

And solving for b we got:

b=-\frac{(7kg*1.5m)}{6kg}=-1.75m

So the coordinates for this new particle are:

(x_4,y_4)=(-1.917,-1.75)m

5 0
3 years ago
Suppose you want to operate an ideal refrigerator with a cold temperature of -10.0ºC , and you would like it to have a coefficie
Arlecino [84]

Answer: temperature of the hot reservoir is 303.52K

Explanation:

Th=temperagture of hot reservoir

Tc=temperature of cold reservoir 263K

Eff=efficiency of the refrigerator

Cop=coefficient of performance

7

Eff=1/cop

Eff=1/7

Eff=0.142

Eff=1-263/th

0.142-1=-263/th

-0.858=-263/th

Th=303.52K

7 0
3 years ago
What is the definition of speed
lana [24]
The rate at which someone or something can move or operate very fast.
4 0
4 years ago
Read 2 more answers
A grapefruit falls from a tree and hits the ground 0.72 s later.
xxTIMURxx [149]

Answer:

<em>The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s</em>

Explanation:

<u>Free Fall Motion </u>

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is g = 9.8 m/s^2.

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The distance traveled by a dropped object is:

\displaystyle y=\frac{gt^2}{2}

Given a grapefruit free falls from a tree and hits the ground t=0.72 s later, we can calculate the height it fell from:

\displaystyle y=\frac{9.8\cdot 0.72^2}{2}

y = 2.54 m

The final speed is computed below:

vf=9.8\cdot 0.72

vf = 7.06 m/s

The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s

6 0
3 years ago
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