Answer:
a) I = 0.363 kg*
b) = 0.82385 kg*
Explanation:
a) If we approximate the skater how a cylinder his moment of inertia is:
I =
I =
I = 0.363 kg*
b) If the skater has his arms extended then:
where : Body’s moment of inertia
: Moment of inertia of the arms
=
= = 0.3176 kg*
= 2 *
= 2 * = 0.50625 kg*
= 0.3176 + 0.50625 = 0.82385 kg*
Answer:
2.064 m
Explanation:
Supposing we have to find the length of the string L also considering the speed of the wave to be 384 m/s.
We know that when a string of a definite length L rigidly held at both ends, there is a standing wave formed where its possible frequencies are given by:
It is given that 535 Hz and 642 Hz are two adjacent frequencies, so if 535 Hz is f_n then 642 Hz will be f_n+1
therefore, we can write
therefore,
plugging values
[tex]L =\frac{384}{2(642-535)}[\tex]
= 2.064 m