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Alex787 [66]
3 years ago
11

Which of these statements best describes a similarity between asteroids and comets?

Physics
2 answers:
NeX [460]3 years ago
7 0

Answer:

D) Both orbit around the sun

Explanation:

Asteroids are rocky bodies having irregular shape and of irregular size. Asteroids are revolve around the sun in elliptical paths. Most asteroids are found in the asteroid belt between orbits of Mars and Jupiter. Ceres is the largest asteroid. Since, it is round in shape also, so it is a dwarf planet.

Comets are composed of rock, dust, ice and frozen gases. Comets lie in Kuiper belt and Oort cloud. Comets liquefy due to heat. Comets orbit the sun in elliptical paths. Comets in Kuiper belt have smaller periods than comets found in the Oort cloud.

Thus, the similarity between asteroids and comets is both orbit around the sun.

weqwewe [10]3 years ago
3 0
The right answer for the question that is being asked and shown above is that: "<span>C) Both liquefy due to heat " the </span>statement that best describes a similarity between asteroids and comets is that <span>C) Both liquefy due to heat </span>
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Relative to the positive horizontal axis, rope 1 makes an angle of 90 + 20 = 110 degrees, while rope 2 makes an angle of 90 - 30 = 60 degrees.

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where R_1,R_2 are the magnitudes of the tensions in ropes 1 and 2, respectively;

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R_1 \sin(110^\circ) + R_2 \sin(60^\circ) - mg = 0

where m=1300\,\rm kg and g=9.8\frac{\rm m}{\mathrm s^2}.

Eliminating R_2, we have

\sin(60^\circ) \bigg(R_1 \cos(110^\circ) + R_2 \cos(60^\circ)\bigg) - \cos(60^\circ) \bigg(R_1 \sin(110^\circ) + R_2 \sin(60^\circ)\bigg) = 0\sin(60^\circ) - mg\cos(60^\circ)

R_1 \bigg(\sin(60^\circ) \cos(110^\circ) - \cos(60^\circ) \sin(110^\circ)\bigg) = -\dfrac{mg}2

R_1 \sin(60^\circ - 110^\circ) = -\dfrac{mg}2

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R_1 = \dfrac{mg}{2\sin(50^\circ)} \approx \boxed{8300\,\rm N}

Solve for R_2.

\dfrac{mg\cos(110^\circ)}{2\sin(50^\circ)} + R_2 \cos(60^\circ) = 0

\dfrac{R_2}2 = -mg\cot(110^\circ)

R_2 = -2mg\cot(110^\circ) \approx \boxed{9300\,\rm N}

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