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pychu [463]
2 years ago
15

Give an example of an object that has potential energy

Chemistry
1 answer:
fredd [130]2 years ago
4 0

Answer:

A book on a shelf

Explanation:

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If you have 222 g of radioisotope with a half-life of 5 days, how much isotope would remain after 15 days?
Dima020 [189]
If the half life is 5 days, you would have to divide 222 by 2 3 times.
so 222/2 =111g
111/2 = 55.5g
55.5/2 = 27.75g

after four half life the mass would be
27.75/2
13.875g

the percent would be
13.875/222
= 6.25%
7 0
3 years ago
Is there DNA in the stucture of prokryotic
azamat

Answer:

i hope this helped

They have no true nucleus as the DNA is not contained within a membrane or separated from the rest of the cell, but is coiled up in a region of the cytoplasm called the nucleoid. Prokaryotic organisms have varying cell shapes.

Explanation:

5 0
3 years ago
Read 2 more answers
Why is there Roman numerals (II) in copper(II) chloride, but no (III) in Aluminum chloride?
Neporo4naja [7]

This is because copper is a transition metals.

Transition metals don't have a definite charge, you can see this on the periodic table. However, Alkali Earth, Alkali, Metalloids, Non-metals, Halogens, Noble Gases, etc, all have a specified charge.

Although, there are exceptions: Zinc, Gold, and Cadmium.

Aluminum is a poor metal, but it has it's own charge (3+).

Therefore, Copper has roman numerals due to the fact that it's a transition metal and Aluminum is a poor metal.

Hope this helps!

6 0
3 years ago
Read 2 more answers
Which of the following gases effuses the fastest at a given temperature?
Sholpan [36]

Answer: -

H₂ will diffuse the fastest.

Explanation: -

According to Graham's Law of Diffusion

The rate of diffusion is inversely proportional to the square root of it's density or molar mass. So the lower the molar mass faster the rate of diffusion.

Molar mass of Ne = 20 g / mol

Molar mass of CH₄ = 12 x 1 + 1 x 4 = 16 g /mol

Molar mass of Ar = 40g / mol

Molar mass of H₂ = 1 x 2 = 2 g / mol

Thus H₂ will diffuse the fastest.

7 0
3 years ago
Determine the concentration of a solution prepared by diluting 25.0 ml of a stock 0.188 m sr(no3)2 solution to 150.0 ml
o-na [289]
We can use the following equation to calculate the concentration of diluted solution.
c1v1 = c2v2 
where c1 is concentration and v1 is volume of stock solution, which is the more concentrated solution.
c2 is concentration and v2 is the volume of diluted solution.
substituting the values in the equation,
0.188 M x 25.0 mL = c2 x 150.0 mL 
c2 = 0.0313 M
concentration of diluted solution is 0.0313 M
8 0
3 years ago
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