Upper M g (s) plus 2 upper H right arrow upper M g (a q) plus upper H subscript 2 (g).
Mg + 2H⁺ → Mg²⁺ + H₂
Explanation:
The net ionic equation is the sum of the oxidation half reactions.
The half-reactions are:
Mg → Mg²⁺ + 2e⁻ Oxidation half reaction
2H⁺ + 2e⁻ → H₂ reduction half reaction
Combining the reactions gives:
Mg + 2H⁺ + 2e⁻ → H₂ + Mg²⁺ + 2e⁻
Since the electrons are balanced, they cancel out of the equation,
This leaves behind;
Mg + 2H⁺ → Mg²⁺ + H₂
Solution:
Ionic equation brainly.com/question/2947744
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The new volume V₂ is 5.4L
The new volume is calculated using Boyle's law formula
That is P₁V₁=P₂V₂
where,
p₁ = 852 torr
V₁ = 27.0
P₂ = 4260 torr
V₂=?
Make V₂ the subject of the formula by diving into both sides of the equation by P₂
V₂ = P₁V₁/P₂
⇒ 852 *
V₂ is, therefore, = 5.4 L
Learn more about Boyle's law here: brainly.com/question/1696010
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Answer:
In-F bond has the largest dipole moment.
Explanation:
Given the electronegativities:
Ge= 2.01
O= 3.44
H= 2.20
P= 2.19
In= 1.78
F= 3.98
B= 2.04
N= 3.04
The bond between Ge and O has an electronegativity difference:
ED= 3.44 - 2.01= 1.43
The bond between H and P has an electronegativity difference:
ED= 2.20 - 2.19= 0.01
The bond between In and F has an electronegativity difference:
ED= 3.98 - 1.78= 2.20
The bond between B and N has an electronegativity difference:
ED= 3.04 - 2.04= 1.00
As In-F bond has the largest electronegativity difference, this is the covalent bond with the largest dipole moment.
There are 2071.4662 grams of glucose in 11.5 moles.
Per 1 mole there are 180.15588 grams of glucose. 180.5588 x 11.5 =2076.4262
Answer:
The molecules inside the ice pack are frozen therefore they are stuck in place. The molecules inside an insulated cup aren't frozen but still stuck inside of their container so that they can not fly out.
Explanation:
