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maw [93]
3 years ago
10

Pc13 is a compound used to make pesticides. A reaction requires that 96.7 kg of pc13 be raised from 31.7 degrees celcius to 69.2

deree celcius. How much energy will this require given that the specific heat of pc13 is o.874 j/kg degree celcius
Physics
1 answer:
siniylev [52]3 years ago
8 0

Answer:

Energy required = 3169.34 Joules.

Explanation:

The quantity of energy (Q) required can be determined by;

Q = mcΔθ

Where: m is the mass, c is the specific heat and Δθ is the change in temperature.

But, m = 96.7 kg, c = 0.874 J/(kg^{o} C), T_{2} = 69.2^{o} and T_{1} = 31.7^{o}.

So that,

Q = mc(T_{2} - T_{1})

   = 96.7 x 0.874 x (69.2^{o} - 31.7^{o})

  = 96.7 x 0.874 x 37.5

  = 3169.3425

Q = 3169.34

   = 3.2 KJ

The amount of energy required is 3169.34 Joules.

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A fixed mass of an ideal gas is heated from 50°C to 80°C (a) at constant volume and (b) at constant pressure. For which case do
soldi70 [24.7K]

Answer:

Specific heat at constant pressure is =  1.005 kJ/kg.K

Specific heat at constant volume is =  0.718 kJ/kg.K

Explanation:

given data

temperature T1 =  50°C

temperature T2 = 80°C

solution

we know energy require to heat the air is express as

for constant pressure and volume

Q  = m ×  c × ΔT     ........................1

here m is mass of the gas and c is specific heat of the gas and Δ T is change in temperature of the gas

here both Mass and temperature difference is equal and energy required is dependent on specific heat of air.

and here at constant pressure Specific heat  is greater than the specific heat at constant volume,

so the amount of heat required to raise the temperature of one unit mass by one degree at constant pressure is

Specific heat at constant pressure is =  1.005 kJ/kg.K

and

Specific heat at constant volume is =  0.718 kJ/kg.K

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