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maw [93]
3 years ago
10

Pc13 is a compound used to make pesticides. A reaction requires that 96.7 kg of pc13 be raised from 31.7 degrees celcius to 69.2

deree celcius. How much energy will this require given that the specific heat of pc13 is o.874 j/kg degree celcius
Physics
1 answer:
siniylev [52]3 years ago
8 0

Answer:

Energy required = 3169.34 Joules.

Explanation:

The quantity of energy (Q) required can be determined by;

Q = mcΔθ

Where: m is the mass, c is the specific heat and Δθ is the change in temperature.

But, m = 96.7 kg, c = 0.874 J/(kg^{o} C), T_{2} = 69.2^{o} and T_{1} = 31.7^{o}.

So that,

Q = mc(T_{2} - T_{1})

   = 96.7 x 0.874 x (69.2^{o} - 31.7^{o})

  = 96.7 x 0.874 x 37.5

  = 3169.3425

Q = 3169.34

   = 3.2 KJ

The amount of energy required is 3169.34 Joules.

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Answer:

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Explanation:

The equation that describes the oscillatory motion is

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In the exercise we are told that the expression is

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b) the frequency or angular velocity

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c) angular velocity and frequency are related

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           f = w / 2π

           f = 3 / 2π

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d) the period

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           T = 1 / f

           T = 1 / 0.477

           T = 20.94 s

e) the phase constant

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f) velocity is defined by

          v = dx / dt

         

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         v = A w

          v = 4 3

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g) the angular velocity is

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           Ke = ½ k x²

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               x = 3.98 m

j) kinetic energy

           K = ½ m v²

for t = 00.1 ²

    v = A w sin 0.10

    v = 4 3 sin 0.10

    v = 1.98 m / s

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