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tester [92]
3 years ago
5

10-10x10+10 ..............​

Physics
1 answer:
cestrela7 [59]3 years ago
4 0

Answer:

10-10x10+10=10-100+10=20-100=-80

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In how many ways can five basketball players be placed in three postitions?
Mazyrski [523]

Answer:

Well if they playing a game like that

4 0
3 years ago
Two forces, F⃗ 1F→1F_1_vec and F⃗ 2F→2F_2_vec, act at a point,F⃗ 1F→1F_1_vec has a magnitude of 8.80 NN and is directed at an an
castortr0y [4]

Answer:

  • Fx = -9.15 N
  • Fy = 1.72 N
  • F∠γ ≈ 9.31∠-10.6°

Explanation:

You apparently want the sum of forces ...

  F = 8.80∠-56° +7.00∠52.8°

Your angle reference is a bit unconventional, so we'll compute the components of the forces as ...

  f∠α = (-f·cos(α), -f·sin(α))

This way, the 2nd quadrant angle that has a negative angle measure will have a positive y component.

  = -8.80(cos(-56°), sin(-56°)) -7.00(cos(52.8°), sin(52.8°))

  ≈ (-4.92090, 7.29553) +(-4.23219, -5.57571)

  ≈ (-9.15309, 1.71982)

The resultant component forces are ...

  • Fx = -9.15 N
  • Fy = 1.72 N

Then the magnitude and direction of the resultant are

  F∠γ = (√(9.15309² +1.71982²))∠arctan(-1.71982/9.15309)

  F∠γ ≈ 9.31∠-10.6°

4 0
3 years ago
How much kinetic energy does an 80 kg man have while running at 3 m/s?
Soloha48 [4]

Hello!

\large\boxed{KE = 360 J}

Use the equation KE = 1/2mv² to solve for the kinetic energy of the man.

We are given the mass and velocity, so plug these values into the equation:

KE = 1/2(80)(3²)

KE = 1/2(720)

KE = 360 J

7 0
3 years ago
What is the difference between transformation of energy and transfer of energy​
Svetllana [295]

Search Results

Featured snippet from the web

In energy transfer, happens from one object to another without changing its form. For example, when you fill a pot of water and sit it on the stove, the water continues to heat until you turn it off. While in a energy transformation, the energy changes forms such as Chemical, kinetic.

6 0
4 years ago
Explorers on a small airless planet used a spring gun to launch a ball bearing vertically upward from the surface at a launch ve
Oksana_A [137]

Answer:

gs = 0.6 m/s^2

Explanation:

Given data:

velocity = 12 m/s

height s = 12t -(1/2) g_s t^2

Given velocity is the derivatives of  height

v(t) = \frac{d}{dt} s(t)

      = \frac{d}{dt}(12t -\frac{1}{2} g_s t^2)

      = 12 - g_s t

when velocity tend to 0 , maximum height is reached

v(t) = 12 - g_s t

0 = 12 - g_s t

g_s = \frac{12}{t}

at t = 20 sec ball reached the max height, so

g_s = \frac{12}{20} = 0.6 m/s^2

5 0
3 years ago
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