Answer:
20.53 g.
Explanation:
- Knowing that every 15.0 g of pure calcium fluoride contains 7.70 g of calcium.
<u>Using cross multiplication:</u>
15.0 g of pure calcium fluoride contains → 7.70 g of calcium.
40.0 g of pure calcium fluoride contains → ??? g of calcium.
<em>∴ The mass of Ca in 40.0 g of calcium fluoride</em> = (7.70 g)(40.0 g)/(15.0 g) = <em>20.53 g.</em>
Answer:
![n=0.0747mol](https://tex.z-dn.net/?f=n%3D0.0747mol)
Explanation:
Hello,
In this case, since we can consider hydrogen gas as an ideal gas, we check the volume-pressure-temperature-mole relationship by using the ideal gas equation:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
Whereas we are asked to compute the moles given the temperature in Kelvins, thr pressure in atm and volume in L as shown below:
![n=\frac{105kPa*\frac{0.009869atm}{1kPa}*1.75L}{0.082\frac{atm*L}{mol*K}*(23+273.15)K} \\\\n=0.0747mol](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B105kPa%2A%5Cfrac%7B0.009869atm%7D%7B1kPa%7D%2A1.75L%7D%7B0.082%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A%2823%2B273.15%29K%7D%20%5C%5C%5C%5Cn%3D0.0747mol)
Best regards.
Hey there!
C₇H₉+ HNO₃ → C₇H₆(NO₂)₃+ H₂O
Our elements: C, H, N, and O.
Balance H.
Ten on the left, eight on the right. Add a coefficient of 2 in front of H₂O.
C₇H₉+ HNO₃ → C₇H₆(NO₂)₃+ 2H₂O
Balance N.
One on the left, three on the right. Add a coefficient of 3 in front of HNO₃.
C₇H₉+ 3HNO₃ → C₇H₆(NO₂)₃+ 2H₂O
This unbalanced H, let's increase the coefficient in front of H₂O from 2 to 3 to rebalance.
C₇H₉+ 3HNO₃ → C₇H₆(NO₂)₃+ 3H₂O
Balance O.
Nine on the left, nine on the right. Already balanced.
Balance C.
Seven on the left, seven on the right. Already balanced.
Our final balanced equation:
C₇H₉+ 3HNO₃ → C₇H₆(NO₂)₃+ 3H₂O
Hope this helps!
Answer:
178 torr
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 5 mL
V₂ = 5 mL (Closed container)
P₁ = 95.0 torr
P₂ = ?
T₁ = 28.0 ºC
T₂ = 290 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (28 + 273.15) K = 301.15 K
T₂ = (290 + 273.15) K = 563.15 K
Using above equation as:
Solving for V₂ , we get:
P₂ = 178 torr