Answer:
Therefore,
The speed of the wave on the longer wire is 95 m/s.
Explanation:
Given:
For Short wire, speed is

Let length of Short and Longer wire be
such that

To Find:
Speed on the longer wire
Solution:
The speed of a pulse or wave on a string under tension can be found with the equation,

Where,
= Tension on the wire
L = Length of Sting
m = mass of String
So here we have,
= same

Therefore,
......equation ( 1 )
And
.......equation ( 2 )
Dividing equation 1 by equation 2 and on Solving we get

Therefore,

Therefore,
The speed of the wave on the longer wire is 95 m/s.
Answer:
4000 kg m/s
Explanation:
<u><em>p=mv</em></u>
- p = momentum in kg m/s
- m = mass in kg
- v = velocity in m/s
substitute values into the formula above to get:
p=1000x4
<u><em>p=4000 kg m/s</em></u>
Answer:
1. Nuclear fusion does not generate radioactive nuclear wastes as nuclear fission does.
2. Nuclear fusion cannot lead to disastrous powerplant explosions as nuclear fission does.
3. More energy is generated during nuclear fusion than in nuclear fission.
Explanation:
Nuclear fusion involves the combination of lighter atoms such as hydrogen to form a heavier nucleus, in the process producing a tremendous amount of energy.
Nuclear fission on the other hand involves splitting a heavy nucleus into two lighter nuclei, releasing energy in the process.
- Nuclear fusion can be more reliable than nuclear fission in energy generation due to the following reasons:
- There are no radioactive waste products obtained as a result of nuclear fusion, unlike nuclear fission. This is because the elements involved in Nuclear fusion are relatively radioactively stable elements.
- The risk of nuclear powerplant explosion due to out of control chain reactions is reduced in nuclear fusion because the reaction can only occur in perfect conditions under high pressure and temperatures <em>(e.g the sun)</em>. When any of these conditions is removed due to a fault, the reaction automatically stops.
- More energy is generated during nuclear fusion than in nuclear fission.
Answer:
The minimun height is 242 [m]
Explanation:
We can solve this problem by using the principle of energy conservation, where potential energy becomes kinetic energy. We will take the point where the Falcon reaches the speed of 69 (m/s), as the point where the potential energy is zero, i.e. it will be the reference point.
At the reference point all potential energy has been transformed into kinetic energy, therefore the kinetic energy can be calculated.
![E_{k}=0.5*m*v^{2} \\ where:\\v = velocity = 69 [m/s]\\m = mass = 480[g] = 0.480[kg]\\E_{k} = kinetic energy [J]\\E_{k} =0.5*0.48*(69)^{2} \\E_{k} =1142.64[J]](https://tex.z-dn.net/?f=E_%7Bk%7D%3D0.5%2Am%2Av%5E%7B2%7D%20%5C%5C%20where%3A%5C%5Cv%20%3D%20velocity%20%3D%2069%20%5Bm%2Fs%5D%5C%5Cm%20%3D%20mass%20%3D%20480%5Bg%5D%20%3D%200.480%5Bkg%5D%5C%5CE_%7Bk%7D%20%3D%20kinetic%20energy%20%5BJ%5D%5C%5CE_%7Bk%7D%20%3D0.5%2A0.48%2A%2869%29%5E%7B2%7D%20%5C%5CE_%7Bk%7D%20%3D1142.64%5BJ%5D)
Now we can calculate the elevation with respect to the reference point using the definition of the potential energy.
![E_{p}=m*g*h\\ E_{p}=E_{k} \\therefore\\h= E_{p}/(m*g)\\h= 1142.64/(.48*9.81)\\h=242[m]](https://tex.z-dn.net/?f=E_%7Bp%7D%3Dm%2Ag%2Ah%5C%5C%20E_%7Bp%7D%3DE_%7Bk%7D%20%5C%5Ctherefore%5C%5Ch%3D%20E_%7Bp%7D%2F%28m%2Ag%29%5C%5Ch%3D%201142.64%2F%28.48%2A9.81%29%5C%5Ch%3D242%5Bm%5D)