Propyl Benzhydryl Ether (continued on next page):
1 answer:
Answer:
See detailed explanation and image attached
Explanation:
1 mole of 1-pentanol reacts with 1 mole of benzhydrol
Number of moles in 1.5 g of benzhydrol = mass/molar mass = 1.5 g/184 g/mol = 0.008 moles of benzhydrol
x moles of 1-pentanol reacts with 0.008 moles of benzhydrol
x = 0.008 moles of 1-pentanol
If 1 mole occupies 22.4 L
0.008 moles occupies 22.4 * 0.008 moles = 0.179 L of 1-pentanol is required.
The mechanism of the formation of n-pentyl benzhydryl ether involves the protonation of the -OH group in benzhydrol. This is followed by loss of water molecule creating a carbocation which is attacked by the 1-pentanol. Abstraction of a proton by a base completes the mechanism, regenerates the acid and yields the n-pentyl benzhydryl ether as shown in the image attached.
The synthesis of diethyl ether occurs by protonation of one ethanol molecule followed by SN2 attack by anothe ethanol molecule and a simultaneous loss of a water molecule. Deprotonation by a base yields the diethyl ether
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Solution :
Given :
Water have quality x = 0.7 (dryness fraction) at around pressure of 200 kPa
The phase diagram is provided below.
a). The phase is a standard mixture.
b). At pressure, p = 200 kPa, T =
Temperature = 120.21°C
c). Specific volume
d). Specific energy ()
e). Specific enthalpy
At
f). Enthalpy at m = 0.5 kg
= 1022.91 kJ
