Question

What is the final, balanced equation that is formed by combining these two half reactions? 2 equations: first: upper C u right arrow upper C u superscript 2 plus, plus 2 e superscript minus. Second: upper N upper O subscript 3 superscript minus, plus 2 e superscript minus, plus 2 upper H superscript plus right arrow upper n upper O subscript 2 superscript minus plus upper H subscript 2 upper O.

Answer 1

Answer: $Cu+NO_3^-+2H^+\rightarrow Cu^{2+}+NO_2^-+H_2O$

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons. The oxidation state of the substance increases.

$Cu\rightarrow Cu^{2+}+2e^-$     (1)

Reduction reaction is defined as the reaction in which a substance gains electrons. The oxidation state of the substance gets reduced.

$NO_3^-+2e^-+2H^+\rightarrow NO_2^-+H_2O$    (2)

Combining (1) and (2) we get:

$Cu+NO_3^-+2H^+\rightarrow Cu^{2+}+NO_2^-+H_2O$

Answer 2

Answer:

b

Explanation: