what is the acceleration of each body of mass 5kg rests on a frictionless table and is connected to a cable that passes over a p
1 answer:
Answer:
6.53 m/s²
Explanation:
Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.
Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:
T = m₁a (1)
m₂g - T = m₂a (2)
substituting T = m₁a in equation 2:
m₂g - m₁a = m₂a
m₂a + m₁a = m₂g
a(m₁ + m₂) = m₂g
a = m₂g / (m₁ + m₂)
a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²
Both objects have an acceleration of 6.53 m/s²
You might be interested in
Answer:
Explanation:
Let:
We need to know for which value of the function
is equal to
:
Therefore, we need to solve for the previous equation for :
Replacing the values of and
:
Subtract 4 from both sides:
Multiply both sides by -1
Divide both sides by 3:
Therefore the value of for which
is
.
Verify the result:
Answer:
A = B = C > D
Explanation:
Work done to stop the disc is given as
so we have
(a) –2 rad/s, 5 rad/s;
(b) 2 rad/s, 5 rad/s;
(c) –2 rad/s, –5 rad/s; and
(d) 2 rad/s, –5 rad/s.
So we have
so we have
A = B = C > D
Explanation:
_z_________z__z_z______
