what is the acceleration of each body of mass 5kg rests on a frictionless table and is connected to a cable that passes over a p
1 answer:
Answer:
6.53 m/s²
Explanation:
Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.
Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:
T = m₁a (1)
m₂g - T = m₂a (2)
substituting T = m₁a in equation 2:
m₂g - m₁a = m₂a
m₂a + m₁a = m₂g
a(m₁ + m₂) = m₂g
a = m₂g / (m₁ + m₂)
a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²
Both objects have an acceleration of 6.53 m/s²
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Answer:
LED bulb = 0.145 A
Incandescent bulb = 0.909 A
CFL bulb = 0.218 A
Explanation:
Given:
Power rating of LED bulb (P₁) = 16 W
Power rating of incandescent bulb (P₂) = 100 W
Power rating of CFL bulb (P₃) = 24 W
Terminal voltage across the circuit (V) = 110 V
We know that, power is related to terminal voltage and current drawn as:
Express this in terms of 'I'. This gives,
Now, calculate the current drawn in each bulb using their respective values.
For LED bulb,
So, current drawn is given as:
For incandescent bulb,
So, current drawn is given as:
For CFL bulb,
So, current drawn is given as:
Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.