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3 years ago

6

A pitcher throws a baseball at 45 m/s. The baseball has a mass of 400 grams. Disregarding air resistance, the baseball's momentu

m when it hits the catcher's mitt is a0 kg*m/s.

1 answer:

MatroZZZ [7]3 years ago

7 0

Momentum = (mass) x (speed)

= (0.4 kg) x (45 m/s)

= 18 kg-m/s in the direction from the mound to the plate.

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2) Why do you think fossil fueled cars are still out numbering alternative and replacement fueled cars even though fossil fuels

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Answer:

Fossil-fueled cars are still outnumbering the alternative and replacement-fueled cars because they are generally cost-effective and are efficient.

Explanation:

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3 years ago

Read 2 more answers

If you could shine a very powerful flashlight beam toward the Moon, estimate the diameter of the beam when it reaches the Moon.

grin007 [14]

To develop this problem it is necessary to apply the Rayleigh Criterion (Angular resolution)criterion. This conceptos describes the ability of any image-forming device such as an optical or radio telescope, a microscope, a camera, or an eye, to distinguish small details of an object, thereby making it a major determinant of image resolution. By definition is defined as:

$\theta = 1.22\frac{\lambda}{d}$

Where,

$\lambda$ = Wavelength

d = Width of the slit

$\theta$ = Angular resolution

Through the arc length we can find the radius, which would be given according to the length and angle previously described.

The radius of the beam on the moon is

$r = l\theta$

Relacing $\theta$

$r = l(\frac{1.22\lambda}{d})$

$r = 1.22\frac{l\lambda}{d}$

Replacing with our values we have that,

$r = 1.22*(\frac{(384*10^3km)(\frac{1000m}{1km})(550*10^{-9}m)}{7*10^{{-2}}})$

$r = 3680.91m$

Therefore the diameter of the beam on the moon is

$d = 2r$

$d = 2 * (3690.91)$

$d = 7361.8285m$

Hence, the diameter of the beam when it reaches the moon is 7361.82m

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