Question

You wish to make a 0.341 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid must you add to obtain a total volume of 75.0 mL of the dilute solution?

Answer 1

Answer:  The volume of concentrated acid  added will be 4.26 ml

Explanation:

The expression used will be dilution law:

$M_1V_1=M_2V_2$

where,

$M_1$ = concentration of stock $HI$ = 6.00 M

$M_2$ = concentration of resulting $HI$ = 0.341 M

$V_1$ = volume of stock $HI$ = ?

$V_2$ = volume of resulting $Hl$ = 75.0 ml

Now put all the given values in the above law, we get the volume of stock $Hl$ added

$6.00\times V_1=0.341\times 75.0$

By solving the terms, we get :

$V_1=4.26ml$

Therefore, the volume of concentrated acid  added will be 4.26 ml