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Julli [10]
3 years ago
15

A wave of frequency 500hz and wave length 50m is traveling into a medium, dertimine the speed of velocity of the wave. formula V

=f×d.​
Physics
2 answers:
kondor19780726 [428]3 years ago
8 0

Ans

Sep 19, 2019 — Wave speed is the distance a wave travels in a given amount of time, such as the ... Wave speed is related to both wavelength and wave frequency. ... The equation for wave speed can be used to calculate the speed of a wave when both ... Frequency = SpeedWavelength or Wavelength = SpeedFrequency.

Explanation:

ololo11 [35]3 years ago
6 0

Answer:

25000m/s

Explanation:

V=fd

V=(500)(50)

V=25000m/s

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A 12,000kg. railroad car is traveling at +2m/s when it
ivann1987 [24]

<u>Answer:</u>

The final velocity of the two  railroad cars is 1.09 m/s

<u>Explanation:</u>

Since we are given that the two cars lock together it shows that the collision is inelastic in nature. The final velocity due to inelastic collision is given by  

\mathrm{V}=\frac{V 1 M 1+V 2 M 2}{M 1+M 2}

where

V= Final velocity

M1= mass of the first object in kgs = 12000

M2= mas of the second object in kgs = 10000

V1= initial velocity of the first object in m/s = 2m/s

V2= initial velocity of the second object in m/s = 0 (given at rest)

Substituting the given values in the formula we get

V = 2×12000 + 0x100012000 + 10000= 2400022000= 1.09 m/s  

\mathrm{V}=\frac{2 \times 1200+0 \times 1000}{12000+10000}=\frac{24000}{22000}=1.09 \mathrm{m} / \mathrm{s}

Which is the final velocity of the two  railroad cars

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3 years ago
You are in the forest with some of your friends. You’re being chased by a very angry and hungry bear.
melomori [17]

Answer:

2m head start or else you done for

Explanation:

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What is the best way to support your hypothesis
Diano4ka-milaya [45]

Answer:

Making a Hypothesis

Explanation:

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4 years ago
Two long, straight wires are parallel and 16 cm apart. One carries a current of 2.9 A, the other a current of 5.7 A. (a) If the
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Explanation:

Given that,

Distance between two long wires, d = 16 cm = 0.16 m

Current in one wire, I_1=2.9\ A

Current in wire 2, I_2=5.7\ A    

The magnetic force per unit length of one wire on the other is given by the following expression as :

\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi d}

\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 2.9\times 5.7}{2\pi \times 0.16}

\dfrac{F}{l}=2.06\times 10^{-5}\ N/m

The current is flowing in opposite direction, the magnetic force acting on it is repulsive. Hence, this is the required solution.

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