Electric current comes from the movement or flow of___

A small convex mirror is placed 60 cm from the pole and on the axis of a large concave mirror of radius of curvature 200 cm. The

umka2103 [35]

Answer:

Calculate 'R' of convex mirror and height of the real image

the radius of the convex mirror is 48cm

Explanation:

Distance between convex and concave mirror is =60cm

Radius of the concave mirror (R) = 200cm

For the concave mirror, u = ∞

V = {R}/{2}=100cm

The object for the convex mirror and the final image is on the pole of the concave mirror, and distance between convex and concave mirror is 60cm

u_1=60-100 =-40cm

Object will be behind the convex mirror

1/f=1/40+1/60

f=24cms

the radius of the convex mirror is 48cm

6 0

3 years ago

A star is known to be moving at 8.46km/s toward the earth. If you observe the spectral line to be at 5.02nm, at what wavelength

anastassius [24]

Answer:

$\lambda_x=5.019858nm$

Explanation:

From the question we are told that

Speed of star $S=8.46km/s$

Distance of spectral line $\lambda_0= 5.02nm$

Generally the equation for wavelength with respect to spectral lines is mathematically given by

$\lambda=\lambda _0 *\frac{v}{c}$

where

$\lambda_0= length\ of\ spectral\ line$

$c=The\ speed\ of\ light$

$v= speed\ of\ moving\ object$

therefore

$\lambda=5.02*10^{-9} *\frac{8.46*10^{12}}{299 792 458*10^9}$

$\lambda=1.42*10^{-4} nm$

Generally the equation for new wavelength is mathematically given as

$\lambda_x=\lambda _0-\lambda$

$\lambda_x=5.02 nm-1.42*10^{-4} nm$

$\lambda_x=5.02-1.42*10^{-4}$

Therefore

$\lambda_x=5.019858nm$

5 0

4 years ago

A sailboat is traveling across the ocean with a speed of 4 m/s when large gusts of wind pick up that starts to accelerate the sa

Ivahew [28]

solution:

Using Cartesian co-ordinate system

Final velocity =v= -4m/s

Initial velocity = u

Acceleration a = m/s²

Time (t).= 60s

By the first kinematical equation

V= u +at

U = v – at

=(-4)-(-3)(60)

176m/s

So, initial velocity was 176m/s

8 0

4 years ago

Why are L waves not usually seen on a seisogram?

bogdanovich [222]

Because P waves are the fastest seismic waves, they will usually be the first ones that your seismograph... sorry couldn't find anymore info from my teacher, well I couldn't remember all of it.

3 0

4 years ago

Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. The downward force on the 2. 67-cm piston tha

Makovka662 [10]

The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.

<h3>What is pascal law?</h3>

Pressure applied to a closed system of fluid will be transfer at each point of the fluid and the boundaries of the system.

Let suppose at the two point of such system the input force apllied is F₁ and output force we get is F₂. The area of this points is A₁ and A₂ respectively. As the pressure at both point is same. Then by the pascal law,

$\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\$

In case of radius,

$\dfrac{F_1}{\pi r_1^2}=\dfrac{F_2}{\pi r_2^2}\\\\\dfrac{F_1}{r_1^2}=\dfrac{F_2}{ r_2^2}$

Two pistons of a hydraulic lift have radii of 2. 67 cm and 20. 0 cm, respectively. Thus,

$r_1=2.67\rm\; cm$

$r_2=20.0\rm\; cm$

The downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is The force applied on second piston is,

$F_2=mg\\F_2=2000\times9.81\\F_2=19620 \rm\; N$

Put the values in the above formula,

$\dfrac{F_1}{2.67^2}=\dfrac{19620}{20^2}\\F_1=\dfrac{19620\times2.67^2}{20^2}\\F_1\approx 350\rm\; N$

Thus, the downward force on the 2. 67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is 350 N.

Learn more about the pascal law here;

brainly.com/question/4262025

#SPJ4

4 0

2 years ago

Electric current comes from the movement or flow of____ charged