Question

when 5 moles of ion oxide react with 25 moles of carbon monoxide what is the moles of the product formed when one of the reagents is used in excess

Answer 1

Answer: 25 moles of product are formed.

Explanation:

The balanced chemical equation will be :

$Fe_2O_3+3CO\rightarrow 2Fe+3CO_2$  

According to stoichiometry :

1 mole of $Fe_2)_3$ require = 3 moles of $CO$

Thus 5 moles of $Fe_2O_3$ will require=$\frac{3}{1}\times 5=15moles$  of $CO$

Thus $Fe_2O_3$ is the limiting reagent as it limits the formation of product and $CO$ is the excess reagent.

As  4 moles of reactant give = 5 moles of product

Thus 20 moles of reactants will give =$\frac{5}{4}\times 20=25moles$ of products