We have as a reagent a salt, lead nitrate (Pb(NO3)2), and an unknown solution that gives us as a product lead chloride (PbCl2). That is, the solution must contain chlorine.
If a chlorine solution is used we will have the following reaction:
So, with a chlorine solution, we will have a white precipitate of lead chloride.
C.) The pressure of the air above the substance. Hope this helps you!
The enthalpy of this reaction is -5315 KJ/mol.
The equation of the reaction is;
2C4H10(g) + 13O2(g) -----> 8CO2 (g) + 10H2O(g)
We know that the enthalpy of reaction can be obtained from the enthalpy of formation of the reactants and products as follows;
ΔHrxn = ΔHf(products) - ΔHf(reactants)
We have the following information from the question;
ΔHf C4H10 = - 125. 6 kJ/mol
ΔHf CO2 = - 393. 5 kJ/mol
ΔHf H2O = - 241. 82 kJ/mol
ΔHf O2 = 0 KJ/mol
Hence;
[(8 × (- 393. 5 )) + (10 × (- 241. 82))] - [2( - 125. 6))]
= -5315 KJ/mol
Learn more: brainly.com/question/13164491
Ugghhhhhhhhhhhhhhhhhhhhhhhhhh
Hey there!:
Option B,CO2 at 353K
*Since most collisions means that highest kinetic energy.
*As we know that kinetic energy of gas molecules is directly proportional to absolute temperature
*More the temperature, More the kinetic energy.
* Hence B is the correct answer as it has highest temperature.
Hope this helps!