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3 years ago

Identify areas of Job growth?

Chemistry

1 answer:

kumpel [21]3 years ago

6 0

Answer:

jobs growth is a figure measured by the Bureau of Labor Statistics (BLS) that tracks how many jobs are created in the country on a monthly basis. The figure is used as a measure of economic expansion and regarded as a litmus test for national economic health

Explanation:

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Which of the following best describes careers that use chemistry?

telo118 [61]

Answer:

Explanation:

7 0

2 years ago

a) One kmol of N2O4 dissociates at 25℃, 1 atm to form an equilibrium ideal gas mixture of N2O4 and NO2 in which the amount of N2

horsena [70]

Answer:

neq N2O4 = 0.9795 mol.....P = 0.5 atm; T = 25°C

Explanation:

ni change eq.

N2O4 1 1 - x 0.8154.....P = 1 atm; T = 25°C

NO2 0 0 + x x

∴ x = neq = Peq.V / R.T.....ideal gas mix

if P = 0.5 atm, T = 25°C; assuming: V = 1 L

⇒ x = neq = ((0.5 atm)(1 L))/((0.082 atm.L/K.mol)(298 K))

⇒ x = neq = 0.0205 mol

⇒ neq N2O4 = 1 - x = 1 - 0.0205 = 0.9795 mol

3 0

3 years ago

Is chemistry hard in grade 11<br>explain to me everything plsss thanks

damaskus [11]

Answer: yes it’s hard

Explanation:

8 0

2 years ago

Read 2 more answers

Write down five laboratory safety rules.

OLEGan [10]

Answer:

Five Laboratory Safety Rules:

1). Do not eat in the laboratory.

2). Do not touch any chemical or reagent unless you are told to do so.

3). Neither play in lab, nor sit on the table.

4). Don't remove labels on any reagent.

5). Don't taste anything in the laboratory, no matter how familiar it appears.

Hope it helps.

5 0

3 years ago

Calculate the number of Na ions and Cl ions and total number of ions in 14.5g of NaCl.

Elanso [62]

Answer:

Number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.

Number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.

Total number of ions = 1.49 × 10²³ + 1.49 × 10²³ = 2.98 × 10²³.

Explanation:

1 mole of any compound contains 6.023 × 10²³ molecules.

molecular weight of NaCl is 23 + 35.5 = 58.5 g.

so, 58.5 grams of NaCl makes 1 mole

⇒ 14.5 g of NaCl = $\frac{14.5}{58.5}$ = 0.248 moles.

⇒ 0.248 mole contains 0.248 × 6.023×10²³ molecules

= 1.49 × 10²³ molecules.

And 1 molecule contains 1 Na ion and 1 Cl ion.

⇒ number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.

⇒ number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.

Total number of ions = 1.49 × 10²³ + 1.49 × 10²³ = 2.98 × 10²³.

6 0

3 years ago