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Komok [63]
3 years ago
7

C) A battery of emf, E drives a current of 0.25A when connected to a 5.5ohms resistor. When

Chemistry
1 answer:
boyakko [2]3 years ago
5 0

Answer:

your ans is battery emf v+1r

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Highlight the claim.
Dahasolnce [82]

Answer:

The claim is: Therefore Mitosis requires less energy than sexual reproduction does.

Explanation:

8 0
3 years ago
PLEASE ANSWER
Otrada [13]

Answer:

The answer is D) White Light!

7 0
3 years ago
At 85°C, the vapor pressure of A is 566 torr and that of B is 250 torr. Calculate the composition of a mixture of A and B that b
Phantasy [73]

Answer:

Composition of the mixture:

x_{A} =0.652=65.2 %

x_{B} =0.348=34.8 %

Composition of the vapor mixture:

y_{A} =0.809=80.9%

y_{B} =0.191=19.1%

Explanation:

If the ideal solution model is assumed, and the vapor phase is modeled as an ideal gas, the vapor pressure of a binary mixture with x_{A} and x_{B} molar fractions can be calculated as:

P_{vap}=x_{A}P_{A}+x_{B}P_{B}

Where P_{A} and P_{B} are the vapor pressures of the pure compounds. A substance boils when its vapor pressure is equal to the pressure under it is; so it boils when P_{vap}=P. When the pressure is 0.60 atm, the vapor pressure has to be the same if the mixture is boiling, so:

0.60*760=P_{vap}=x_{A}P_{A}+x_{B}P_{B}\\456=x_{A}P_{A}+(1-x_{A})P_{B}\\456=x_{A}*(P_{A}-P_{B})+P_{B}\\\frac{456-P_{B}}{P_{A}-P_{B}}=x_{A}\\\\\frac{456-250}{566-250}=x_{A}=0.652

With the same assumptions, the vapor mixture may obey to the equation:

x_{A}P_{A}=y_{A}P, where P is the total pressure and y is the fraction in the vapor phase, so:

y_{A} =\frac{x_{A}P_{A}}{P}=\frac{0.652*566}{456} =0.809=80.9 %

The fractions of B can be calculated according to the fact that the sum of the molar fractions is equal to 1.

7 0
3 years ago
Is it possible to have a relative atomic mass less then 24 or more than 26
qwelly [4]
I think Magnesium not sure because the relative atomic mass of magnesium is 24,31.
6 0
3 years ago
How many protons are there in 20.02 mol of neon (Ne)?
Anettt [7]
In order to determine the number of protons in 20.02 mol of Ne, we use Avogadro's number to convert the number of moles to number of atoms, 1 mol = 6.022 x 10^23 atoms. From there, we must know the number of protons in a Neon atom, which is 10. Thus, the formula will be:
(20.02 mol Ne)x(6.022 x 10^23 atoms/mol)x(10 protons/1 atom Ne) = 1.2056 x 10^26 protons 


7 0
3 years ago
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