Answer:
Explanation:
A confined aquifer is one that's impermeable and does not allow seepage's of water through it.
An unconfined aquifer is a body of water that has permeable membranes which allows passage of water through it.
There will be little or no transmission of water trough these bodies of water.
Answer:
A)
Current drawn by toaster = 15.33 A
Current drawn by electric frying pan = 11.83 A
Current drawn by lamp = 0.58 A
B)
The fuse will definitely blow up since the current drawn by three devices (27.74 A) is way higher than 15 A fuse rating.
Explanation:
There are three devices plugged into the same outlet.
Toaster = 1840 W
Electric frying pan = 1420 W
Lamp = 70 W
Since the three devices are connected in parallel therefore, the voltage across them will be same but the current drawn by each will be different.
A) What current is drawn by each device?
The current flowing through the device is given by
I = P/V
Where P is the power and V is the voltage.
Current drawn by toaster:
I = 1840/120
I = 15.33 A
Current drawn by electric frying pan:
I = 1420/120
I = 11.83 A
Current drawn by lamp:
I = 70/120
I = 0.58 A
B) Will this combination blow the 15-A fuse?
The total current drawn by all three devices is
Total current = 15.33 + 11.83 + 0.58
Total current = 27.74 A
Therefore, the fuse will definitely blow up since the current drawn by three devices (27.74 A) is way higher than 15 A fuse rating.
Answer:
Explanation:
There are three points in time we need to consider. At point 0, the mango begins to fall from the tree. At point 1, the mango reaches the top of the window. At point 2, the mango reaches the bottom of the window.
We are given the following information:
y₁ = 3 m
y₂ = 3 m − 2.4 m = 0.6 m
t₂ − t₁ = 0.4 s
a = -9.8 m/s²
t₀ = 0 s
v₀ = 0 m/s
We need to find y₀.
Use a constant acceleration equation:
y = y₀ + v₀ t + ½ at²
Evaluated at point 1:
3 = y₀ + (0) t₁ + ½ (-9.8) t₁²
3 = y₀ − 4.9 t₁²
Evaluated at point 2:
0.6 = y₀ + (0) t₂ + ½ (-9.8) t₂²
0.6 = y₀ − 4.9 t₂²
Solve for y₀ in the first equation and substitute into the second:
y₀ = 3 + 4.9 t₁²
0.6 = (3 + 4.9 t₁²) − 4.9 t₂²
0 = 2.4 + 4.9 (t₁² − t₂²)
We know t₂ = t₁ + 0.4:
0 = 2.4 + 4.9 (t₁² − (t₁ + 0.4)²)
0 = 2.4 + 4.9 (t₁² − (t₁² + 0.8 t₁ + 0.16))
0 = 2.4 + 4.9 (t₁² − t₁² − 0.8 t₁ − 0.16)
0 = 2.4 + 4.9 (-0.8 t₁ − 0.16)
0 = 2.4 − 3.92 t₁ − 0.784
0 = 1.616 − 3.92 t₁
t₁ = 0.412
Now we can plug this into the original equation and find y₀:
3 = y₀ − 4.9 t₁²
3 = y₀ − 4.9 (0.412)²
3 = y₀ − 0.83
y₀ = 3.83
Rounded to two significant figures, the height of the tree is 3.8 meters.
Answer: yes
Explanation: People post bad things that i think should get taken down i was on an app the other day and people were posting bad things
Answer:
461 C
862 F
Explanation:
The specific gas constant for CO2 is
R = 189 J/(kg*K)
Using the gas state equation:
p * v = R * T
T = p * v / R
v = 1/δ
T = p / (R * δ)
T = 9.3*10^6 / (189 * 67) = 734 K
734 - 273 = 461 C
461 C = 862 F
