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3 years ago

Whoever could answer this I would make Brainliest

Physics

1 answer:

skad [1K]3 years ago

3 0

Answer:

1. the rocks at the bottom of the aquarium

2.the fish and maybe the plants (if you use live plants)

3. fish interact with there no living things like how one would hide in the grass or something like that.

4. decorations (like a cave or fake house, tho the aquarium its self is a home)

5.they would die, and rot.

Explanation:

rocks are nonliving

fish are living things and so are plants

fish can hide in the plants

the fish can "live" in the decorations, but the aquarium itself is its home.

if something reaches the end of its life span it dies.

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Physical properties of minerals graphic organizer

Nadusha1986 [10]

The answer is in the attachment
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4 0

3 years ago

In models of magnetic and electric fields, why are field vectors depicted by arrows?

taurus [48]

The arrows in models of magnetic and electric fields show both their magnitude and direction.

In Physics, a vector refers to a quantity that has both magnitude and direction. Hence, a vector always points in a given direction. The direction in which the arrow points is the direction of the vector in space.

In models of magnetic and electric fields, field vectors depicted by arrows because they represent both their magnitude and direction. The length of the arrow shows magnitude.

Learn more: brainly.com/question/102477

7 0

2 years ago

-Which of the following wires will have the least resistance?

scoray [572]

The wires that will have the least resistance is :
C. A short thick wire
in order to get the least resistence, you need the wire to be the lowest in length and the highest in Area

hope this helps

7 0

3 years ago

Read 2 more answers

You attach a meter stick to an oak tree, such that the top of the meter stick is 2.27 meters above the ground. later, an acorn f

Alexandra [31]

The acorn was at a height of 4.15 m from the ground before it drops.

The acorn takes a time t to fall through a distance h₁, which is the length of the scale. When the acorn reaches the top of the scale, its velocity is u.

Calculate the speed of the acorn at the top of the scale, using the equation of motion,

$s=ut+ \frac{1}{2} at^2$

Since the acorn falls freely under gravity, its acceleration is equal to the acceleration due to gravity g.

Substitute 2.27 m for s (=h₁), 0.301 s for t and 9.8 m/s² for a (=g).

$s=ut+ \frac{1}{2} at^2\\ (2.27 m)=u(0.301s)+\frac{1}{2}(9.8m/s^2)(0.301s)^2\\ u=\frac{1.8261m}{0.301s} =6.067m/s$

If the acorn starts from rest and reaches a speed of 6.067 m/s at the top of the scale, it would have fallen a distance h₂ to achieve this speed.

Use the equation of motion,

$v^2=u^2+2as$

Substitute 6.067 m/s for v, 0 m/s for u, 9.8 m/s² for a (=g) and h₂ for s.

$v^2=u^2+2as\\ (6.067m/s)^2=(0m/s)^2+2(9.8m/s^2)h_2\\ h_2=\frac{(6.067m/s)^2}{2(9.8m/s^2)} =1.878 m$

The height h above the ground at which the acorn was is given by,

$h=h_1+h_2=(2.27 m)+(1.878 m)=4.148 m$

The acorn was at a height 4.15m from the ground before dropping down.

3 0

3 years ago

In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the max

Sav [38]

Answer:

the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94

Explanation:

Given that ;

the top speed of Cheetahs is almost 60 mph

In cornering abilities ; the maximum centripetal acceleration of a cheetah was measured to be = 19 m/s^2

The objective of this question is to determine the what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?

From the knowledge of Newton's Law;

we knew that ;

Force F = mass m × acceleration a

Also;

The net force $F_{net}$ = frictional force $\mu_k mg$