The load is placed at distance 0.4 L from the end of
area.
<h3>What is meant by torque?</h3>
The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is torque.
Let the beam is of length L
Now the stress on both the end is the same now we can say that torque on the beam due to two forces must be zero

also, we know that stress at both ends are same


Now from two equations we have

solving the above equation we have

so the load is placed at distance 0.4 L from the end of
area.
The complete question is:
47. the beam is supported by two rods ab and cd that have cross-sectional areas of
and
, respectively. determine the position d of the 6-kn load so that the average normal stress in each rod is the same.
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Answer:
The stress in the rod is 39.11 psi.
Explanation:
The stress due to a pulling force is obtained dividing the pulling force by the the area of the cross section of the rod. The respective area for a cylinder is:

Replacing the diameter the area results:

Therefore the the stress results:

Answer:
See explaination
Explanation:
Let's define tuple as an immutable list of Python objects which means it can not be changed in any way once it has been created.
Take a look at the attached file for a further detailed and step by step solution of the given problem.
Answer:
I am gonna say it is AMERICAN
It is to be noted that it is impossible to find the Maclaurin Expansion for F(x) = cotx.
<h3>What is
Maclaurin Expansion?</h3>
The Maclaurin Expansion is a Taylor series that has been expanded around the reference point zero and has the formula f(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!
<h3>
What is the explanation for the above?</h3>
as indicated above, the Maclaurin infinite series expansion is given as:
F(x)=f(0)+f′. (0) 1! x+f″ (0) 2! x2+⋯+f[n](0)n!
If F(0) = Cot 0
F(0) = ∝ = 1/0
This is not definitive,
Hence, it is impossible to find the Maclaurin infinite series expansion for F(x) = cotx.
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