Answer:
Explanation:
Height h = 1.03m
Volume v = 3780 gallons = 3780 * 0.0037851m^3 = 14.3073m^3
Time t = 13.5 mins = 13.5 * 60 = 810 seconds
Length of pool L = 14 inch = 14 * 2.54 = 35.56cm
width of pool b = 48 inch = 48 * 2.54 = 121.92 cm
a.) Consider the bernoulli's equation is given as:
consider the equation of bernoulli at the top of the pool
where atm pressure
At the top of the pool , substitute in V_1 in equation (2)
Hence equation (3) serves as the bernoullis equation at the top.
b.) Consider the equation of bernoulli's at the opening of the pool
where atm pressure and
Hence equation (6) serves as the bernoullis equation of water at the opening of the pool.
c.) Consider the equation (3) and (4)
Hence velocity is
d.) consider (7)
This is the norminal value of velocity
e.) consider the equation of flow rate interval of v and t
flow(t)= hence this is the flow rate
f.) Consider the equation cross sectional area in terms of V,v2 and t
hence this serves as the cross sectional area.
g.) Consider the equation of area from equation (8)
