Question

A 2.60 kg lion runs at a speed of 5.00 m/s until he sees his prey. The lion then speeds up 8.00 m/s to catch it. How much work did do after he speeds up?

Answer 1

Answer: 50.7 J

Explanation:

Given

mass of lion is  $m=2.6\ kg$

The initial speed of the lion is $v_1=5\ m/s$

increased speed of lion is $v_2=8\ m/s$

Initially, its kinetic energy is $K_1=\frac{1}{2}mv_1^2$

Final kinetic energy $k_2=\frac{1}{2}mv_2^2$

work did by lion after speed up is $k_2-k_1$

$\Rightarrow W=\dfrac{1}{2}\times 2.6[8^2-5^2]\\\\\Rightarrow W=1.3\times [39]=50.7\ J$