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Natali5045456 [20]
3 years ago
8

What kind of error duo you think is used in the side-view mirror of cars?

Physics
1 answer:
tatyana61 [14]3 years ago
6 0

Answer:

<em><u>Here's a list of the 10 most common mistakes </u></em>we humans make when operating an automobile.

Crossing Lanes While Turning.

Using Your Daylights At Night. ...

Bad Seating Position. ...

Riding The Brakes. ...

Leaving Your High Beams On. ...

Not Using Your Turn Signal. ...

Driving Slowly In The Passing Lane. ...

Not Adjusting The Mirrors Properly. ...

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The second Law of Thermodynamics states that: A. spontaneous processes are characterized by the overall conversion of order to d
Georgia [21]

Answer:

Spontaneous processes are characterized by the overall conversion of order to disorder.

Explanation:

The second law of thermodynamics states that: A spontaneous process occurs only if there is an increase in entropy of a system and its surroundings.

Entropy, S, is a measure of the randomness or disorder of a system. It is measured in J/Kmol.

The change in entropy, ∆S = ∆H/T

Where ∆H = change in enthalpy, T = Temperature in Kelvin.

For,

I. An endothermic reaction, ∆S = positive (that is, ∆S is greater than zero), there is an increase in entropy, therefore, the reaction is spontaneous.

II. An exothermic reaction, ∆S = negative (that is, ∆S is less than zero) there is a decrease in entropy, so, the reaction is non-spontaneous.

III. A system at equilibrium, ∆S = 0.

Then,

The standard change in entropy of a reaction, ∆So reaction , is the difference in the standard entropies between products and reactants:

∆So reaction = n ∆Soproducts - m ∆Soreactants

Where, = sigma = sum of,

∆ = delta = change in,

n and m = stoichiometric coefficients of the products and reactants respectively.

Furthermore, the entropy of the system and surroundings is referred to as the entropy of the universe.

∆Suniverse = ∆Ssurroundings + ∆Ssystem.

Processes leading to an increase in entropy include melting, heating, vaporization, dissolving.

8 0
3 years ago
An object is moving at constant speed of 5mph &amp; the net force = 0 N. Which statement is true? a The object will stop moving.
ra1l [238]

Answer:

The object will continue moving at 5 mph ( b )

Explanation:

For an object moving at a constant speed, the forces acting on it cancels each other out, or there are no external forces atall. hence its net force = 0 N . so the true statement is that the object will continue moving at its constant speed of 5 mph because its net force = 0 N

7 0
3 years ago
You throw a ball upwards at 22.0 m/s how high will it go?
Alex

Answer:

Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at

2

=20(2)+0.5(−10)(2)

2

=20m

Thus, total distance for maximum height is 45 m

s=ut+0.5at

2

45=0+0.5(10)(t ′ )

2

t

′

=3s

Total time= 3+2= 5s

Explanation:

TAKE 22.0 IN PLACE OF 20 U WILL GET YR ANSWER

HOPE IT HELPS

3 0
3 years ago
Describe how energy is transferred through a mechanical wave. Enter your answer in the space provided.
Anni [7]

Mechanical waves transfer energy by including vibration in the propagation medium electromagnetic waves do not require a medium for propagation but still transfer energy by having an electric and magnetic field propagate perpendicular to one another. Hope this helps:)

7 0
3 years ago
A man of mass 80.0 kg stands on a platform of mass 40.0 kg. He pulls on a rope that is fastened to the platform and runs over a
Vesnalui [34]

Answer:F=648 N

Explanation:

Given

mass of man m_1=80 kg

mass of Platform m_2=40 kg

acceleration of system a=1 m/s^2

Let F be the force with which man pulls the rope which will also create a tension of F in rope

From Diagram

2F-(m_1+m_2)g=(m_1+m_2)a

2F=(m_1+m_2)(g+a)

F=\frac{(m_1+m_2)(g+a)}{2}

F=\frac{(80+40)(9.8+1)}{2}

F=\frac{1296}{2}

F=648 N

7 0
3 years ago
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