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bija089 [108]
3 years ago
10

WHAT PARTS OF THE BRAKE LAMP SYSTEM CAN FAIL? DESCRIBE HOW? Help me ASAP please

Engineering
1 answer:
adell [148]3 years ago
5 0

Answer:

Explanation:

Brake systems are most likely to fail at the ends.  One of the most common problems is a trailer lighting splitter is left on. With time and usage, the fuse can blow interrupting the signal path from the switch to the bulb.

Answered by the <u><em>ONE </em></u>& <u><em>ONLY</em></u> <u><em>#QUEEN aka #DRIPPQUEENMO</em></u>

<u><em>HOPE THIS HELPED!!!</em></u>

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Find the rate of heat transfer through a 6 mm thick glass window with a cross-sectional area of 0.8 m2 if the inside temperature
kiruha [24]

Answer:

6.9

Explanation:

I had the same question lol your welcomr if itd not right in sorry

3 0
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Determine whether or not each of the following four transaction execution histories is serializable. If a history is serializabl
ludmilkaskok [199]

Answer:

Option D. w1[x] w2[u] w2[y] w1[y] w3[x] w3[u] w1[z]

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The execution in the option D is correct. This is because there is more than one reasonable criterion.

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the coil polarity in a waste spark system is determined by the direction in which the coil is wound (left hand rule for conventi
zaharov [31]
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3 years ago
A well-designed product will increase?​
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Answer:

true

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8 0
2 years ago
A work element in a manual assembly task consists of the following MTM-1 elements: (1) R16C, (2) G4A, (3) M10B5, (4) RL1, (5) R1
ella [17]

Answer:

a)

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b) 3.1 secs

Explanation:

a) Determine the normal times in TMUs for these motion elements

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b ) Determine the total time for this work element in seconds

first we have to determine the total TMU = ∑ TMU = 86.4 TMU

note ; 1 TMU = 0.036 seconds

hence the total time for the work in seconds = 86.4 * 0.036 = 3.1 seconds

7 0
3 years ago
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